Each of these extreme value problems has a solution with both a maximum value and a minimum
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Each of these extreme value problems has a solution with both a maximum value and a minimum value. Use Lagrange multipliers to find the extreme values of the function subject to the given constraint.
f (x, y, z) = ln(x2 + 1) + ln(y2 + 1) + ln(z2 + 1); x2 + y2 + z2 = 12
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fx y z lnx 1 lny 1 ln2 1 gx y z x y x 12 Then Vf XVg 2x 2y 22 2z i 2y y 1 x 1 y 1 z 1 2 1 2x 2y 2z s...View the full answer
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