Given y = (u) and u = g(x), find dy/dx = (g(x))g(x). y = -sec u, u
Question:
Given y = ƒ(u) and u = g(x), find dy/dx = ƒ′(g(x))g′(x).
y = -sec u, u = 1/x + 7x
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To use the chain rule to find dydx we need to first find u and gx and t...View the full answer
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Related Book For 
Thomas Calculus Early Transcendentals
ISBN: 9780321884077
13th Edition
Authors: Joel R Hass, Christopher E Heil, Maurice D Weir
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