In Exercises 1922, evaluate the line integral along the given path. Se C: r(t) = ti +

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In Exercises 19–22, evaluate the line integral along the given path.

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Calculus Of A Single Variable

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Authors: Ron Larson, Bruce H. Edwards

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In Exercises 5356, evaluate the line integral along the path C given by x = 2t, y = 4t, where 0 t 1. Lo (y - x) dx + 5xy dy
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In Exercises 1922, evaluate the line integral along the given path. Sa C: r(t) = 12ti + 5tj + 84tk 0 t 1 2xyz ds
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In Exercises 1922, evaluate the line integral along the given path. Se C: r(t) = ti +

Question:

Se C: r(t) = ti + (2 t)j 0 ≤t≤ 2 3(x - y) ds

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To evaluate the line integral C 3xy ds along the given path C rt ...View the full answer

Calculus Of A Single Variable

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