Solve for k. a. e 5k = 1/4 b. 80e k = 1 c. e (ln 0.8)k

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Solve for k.

a. e^5k = 1/4

b. 80e^k = 1

c. e^{(ln 0.8)k} = 0.8

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Thomas Calculus Early Transcendentals

ISBN: 9780321884077

13th Edition

Authors: Joel R Hass, Christopher E Heil, Maurice D Weir

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Question Posted: Apr 13, 2023 05:06 AM

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Solve for k. a. e 5k = 1/4 b. 80e k = 1 c. e (ln 0.8)k

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a To solve for k in the equation e5k 14 we can take the natural logarithm of bot...View the full answer

Thomas Calculus Early Transcendentals

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