Solve for t. a. e -0.3t = 27 b. e kt = 1/2 c. e (ln 0.2)t

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Solve for t.

a. e^-0.3t = 27

b. e^kt = 1/2

c. e^{(ln 0.2)t} = 0.4

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Thomas Calculus Early Transcendentals

ISBN: 9780321884077

13th Edition

Authors: Joel R Hass, Christopher E Heil, Maurice D Weir

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Question Posted: Apr 13, 2023 12:32 AM

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Solve for t. a. e -0.3t = 27 b. e kt = 1/2 c. e (ln 0.2)t

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Thomas Calculus Early Transcendentals

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