Suppose x, y, and z are consecutive terms in a geometric sequence If x y z 103 and x 2 y 2 z 2 6901, find the value of y Let r be the common ratio so y xr and z yr xr 2

Question: Suppose x, y, and z are consecutive terms in a geometric sequence. If x + y + z = 103 and x 2 + y

Suppose x, y, and z are consecutive terms in a geometric sequence. If x + y + z = 103 and x² + y² + z² = 6901, find the value of y. Let r be the common ratio so y = xr and z = yr = xr².

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