Question: 5.2.2 Suppose that 100 tags, numbered 1;2; : : : ; 100, are placed into an urn, and 10 tags are drawn successively, with replacement.

5.2.2 Suppose that 100 tags, numbered 1;2; : : : ; 100, are placed into an urn, and 10 tags are drawn successively, with replacement. Let A be the event that no tag is drawn twice. Show that

Pr{A} = = (1-10) (1-170) (1 - 120) = 2 = 0.6282.

Use the approximation

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to get

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Interpret this in terms of the law of rare events.

Pr{A} = = (1-10) (1-170) (1 - 120) = 2 = 0.6282.

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