Consider the HMM shown in Figure 11.19 that has three hidden states 1, 2, and 3, and emits two output symbols: U and V. When it is in state 1, it is equally likely to emit either symbol. When it is in state 2, the probability that it emits the symbol U is 0.1, and the probability that it emits the symbol V is 0.9. Finally, when it is in state 3, the probability of emitting the symbol U is 0.9 and the probability of emitting the symbol V is 0.1.