Let (left(B_{t}ight)_{t geqslant 0}) be a (mathrm{BM}^{1}). Show that (mathbb{P}left(sup _{s leqslant t}left|B_{s}ight| geqslant xight) leqslant 2

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Let \(\left(B_{t}ight)_{t \geqslant 0}\) be a \(\mathrm{BM}^{1}\). Show that \(\mathbb{P}\left(\sup _{s \leqslant t}\left|B_{s}ight| \geqslant xight) \leqslant 2 \mathbb{P}\left(\left|B_{t}ight| \geqslant xight), x, t \geqslant 0\).

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