Consider the following code skeleton in C Explain why the compiler wont allow the second call Give an example of bad things that could happen if it did include using std 1ist class foo class bar public foo static void print all(list L) list LF list LB print all (LF) print all (LB) works fine static...

Since every bar is a foo it is tempting to think that anything printall might do to elements of a ...

Consider the following code skeleton in C++: Explain why the compiler wont allow the second call. Give

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Consider the following code skeleton in C++:

$#include using std::1ist; class foo {... class bar : public foo { ... static void print_all(list &L) { .. list LF; list LB; print_all (LF); print_all (LB); // works fine // static semantic error$

Explain why the compiler won’t allow the second call. Give an example of bad things that could happen if it did.

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Programming Language Pragmatics

ISBN: 9780124104099

4th Edition

Authors: Michael L. Scott

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Question Posted: Nov 26, 2020 01:22 AM

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Consider the following code skeleton in C++: Explain why the compiler wont allow the second call. Give

Question:

#include using std::1ist; class foo {... class bar : public foo { ... static void print_all(list &L) { .. list LF; list LB; print_all (LF); print_all (LB); // works fine // static semantic error

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Programming Language Pragmatics

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