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How many grams of Li3N can be formed from 1.75 moles of Li? Assume an excess of nitrogen. 6 Li(s) + N2(g) 2 Li3N

How many grams of Li3N can be formed from 1.75 moles of Li? Assume an excess of nitrogen.
6 Li(s) + N2(g) → 2 Li3N (s)

A. 18.3 g Li3N
B. 20.3 g Li3N
C. 58.3 g Li3N
D. 61.0 g Li3N
E. 15.1 g Li3N

Two samples of calcium fluoride are decomposed into their constituent elements. The first sample produced 0.154 g of calcium and 0.146 g of fluorine. If the second sample produced 294 mg of fluorine, how many g of calcium were formed?
A. 0.280 g
B. 3.09 × 102 g
C. 3.13 g
D. 0.309 g
E. 2.80 × 102 g

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