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Multiple Choice Questions: 1. Which of the choices below constitutes a simultaneous solution to these equations? A. x = 1, y = 1.5 B. x

Multiple Choice Questions:


1. Which of the choices below constitutes a simultaneous solution to these equations?

A. x = 1, y = 1.5

B. x = .5, y = 2

C. x = 0, y = 3

D. x = 2, y = 0

E. x = 0, y = 0


2. What combination of x and y will yield the optimum for this problem?

A. x = 2, y = 0

B. x = 0, y = 0

C. x = 0, y = 3

D. x = 1, y = 5

E. none of the above


3. What combination of x and y will provide a minimum for this problem?

A. x = 0, y = 0

B. x = 0, y = 3

C. x = 0, y = 5

D. x = 1, y = 2.5

E. x = 6, y = 0


4. The production planner for Fine Coffees, Inc. produces two coffee blends: American (A) and British (B). Two of his resources are constrained: Columbia beans, of which he can get at most 300 pounds (4,800 ounces) per week; and Dominican beans, of which he can get at most 200 pounds (3,200 ounces) per week. Each pound of American blend coffee requires 12 ounces of Colombian beans and 4 ounces of Dominican beans; while a pound of British blend coffee uses 8 ounces of each type of bean. Profits for the American blend are $2.00 per pound, and profits for the British blend are $1.00 per pound. [Answer the following question]

What is the objective function?

A. $1 A + $2 B = Z

B. $12 A + $8 B = Z

C. $2 A + $1 B = Z

D. $8 A + $12 B = Z

E. $4 A + $8 B = Z


5. A local bagel shop produces two products: bagels (B) and croissants (C). Each bagel requires 6 ounces of flour, 1 gram of yeast, and 2 tablespoons of sugar. A croissant requires 3 ounces of flour, 1 gram of yeast, and 4 tablespoons of sugar. The company has 6,600 ounces of flour, 1,400 grams of yeast, and 4,800 tablespoons of sugar available for today's production run. Bagel profits are 20 cents each, and croissant profits are 30 cents each. [Answer the following question]

What is the objective function?

A. $0.30 B + $0.20 C = Z

B. $0.60 B + $0.30 C = Z

C. $0.20 B + $0.30 C = Z

D. $0.20 B + $0.40 C = Z

E. $0.10 B + $0.10 C = Z

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