0 pts) 2. Use SCM theory for all calculations pertaining to this problem. Automatic -10 points for using LCM equations. Use the following MOSFET data as needed: NMOS: V70,n=0.4 V, kn = 2 mA/V2, 12F) = 0.8 V, Y=0.2 V12, 2n = 0 V-1, EcL1 = 0.5 V PMOS: Vro.p=-0.4 V, kp= 1 mA/V2, 120x1 = 0.8 V, 7p = 0.2 V12, 2p = 0 V-, EcpLp = 2.0 V 3 V Vou pF (a) **Calculate tfall using SCM theory and exact calculations that came from solving the governing differential equation. Use established results. Do not try to solve the differential equations again; that has already been done, so you should use those results. (15 pts] CMOS inverter, load discharging (through NMOS running in saturation 20 Vos -V..+E_yL4 (V. -V) Atsar k,(E_1.) (Vos-V..) CMOS inverter, load discharging (through NMOS running in triode): In 1 Cood (VG -V) ki Chemie At criode) 2(Vgs -V)-(v.) (v.) | 2(Vas -V)-(v.) (v.) 2 (2() Vas -V...)-(V.) In EL 2(VGs -V)-(v.) + AS 1 CMOS inverter, load charging (from PMOS running in saturation): 2Coed Ysg+V7.p + E.L k,(E.L) (vso +V,wp) -(V-V.) CMOS inverter, load charging (from PMOS running in triode): [ 2(Vs& +V,.p) -(Vpo -V)(Vpp -V.) Cload (vsa +V,.2) 2(Vso +V.P)-(VD-V.) || (VDD - V. k 2 2(Vso +V,.p)-(Vpp-V) E.pl 2(Vsa +Vr.p) -(Vpp -V.) RTL inverter, load discharging (through NMOS running in saturation): Atsar) = Road In a +V. a+V In Attriode) | (V so = + In RTL inverter, load discharging (through NMOS running in triode): At triede) BE bf 2c = RC load 1 In b2-4ac f + In 2c (20V, +b - Vb? - 4ac )(20V. +b+Vb2-4ac (20V, +b+ Vo? - 4ac )(20V. +6 Vb2 - 4ac) a+bV, +cV2 a+bV+V2 0 pts) 2. Use SCM theory for all calculations pertaining to this problem. Automatic -10 points for using LCM equations. Use the following MOSFET data as needed: NMOS: V70,n=0.4 V, kn = 2 mA/V2, 12F) = 0.8 V, Y=0.2 V12, 2n = 0 V-1, EcL1 = 0.5 V PMOS: Vro.p=-0.4 V, kp= 1 mA/V2, 120x1 = 0.8 V, 7p = 0.2 V12, 2p = 0 V-, EcpLp = 2.0 V 3 V Vou pF (a) **Calculate tfall using SCM theory and exact calculations that came from solving the governing differential equation. Use established results. Do not try to solve the differential equations again; that has already been done, so you should use those results. (15 pts] CMOS inverter, load discharging (through NMOS running in saturation 20 Vos -V..+E_yL4 (V. -V) Atsar k,(E_1.) (Vos-V..) CMOS inverter, load discharging (through NMOS running in triode): In 1 Cood (VG -V) ki Chemie At criode) 2(Vgs -V)-(v.) (v.) | 2(Vas -V)-(v.) (v.) 2 (2() Vas -V...)-(V.) In EL 2(VGs -V)-(v.) + AS 1 CMOS inverter, load charging (from PMOS running in saturation): 2Coed Ysg+V7.p + E.L k,(E.L) (vso +V,wp) -(V-V.) CMOS inverter, load charging (from PMOS running in triode): [ 2(Vs& +V,.p) -(Vpo -V)(Vpp -V.) Cload (vsa +V,.2) 2(Vso +V.P)-(VD-V.) || (VDD - V. k 2 2(Vso +V,.p)-(Vpp-V) E.pl 2(Vsa +Vr.p) -(Vpp -V.) RTL inverter, load discharging (through NMOS running in saturation): Atsar) = Road In a +V. a+V In Attriode) | (V so = + In RTL inverter, load discharging (through NMOS running in triode): At triede) BE bf 2c = RC load 1 In b2-4ac f + In 2c (20V, +b - Vb? - 4ac )(20V. +b+Vb2-4ac (20V, +b+ Vo? - 4ac )(20V. +6 Vb2 - 4ac) a+bV, +cV2 a+bV+V2