0 Question 1 v On average, a banana will last 7 days from the time it is purchased in the store to the time it is too rotten to eat. Is the mean time to spoil greater if the banana is hung from the ceiling? The data show results of an experiment with 15 bananas that are hung from the ceiling. Assume that that distribution of the population is normal. 5.7, 8.4, 9.4, 8.5, 7.9, 7.9, 6.8, 8.9, 7.3, 5.9, 7.2, 9.1, 6.6, 8.5, 6.4 What can be concluded at the the o: = 0.01 level of significance level of significance? at For this study, we should use b. The null and alternative hypotheses would be: c. The test statistic = (please show your answer to 3 decimal places.) d. The p-value = (Please show your answer to 4 decimal places.) e. The p-value is o: f. Based on this, we should the null hypothesis. g. Thus, the final conclusion is that O The data suggest the populaton mean is significantly more than 7 at a = 0.01, so there is statistically significant evidence to conclude that the population mean time that it takes for bananas to spoil if they are hung from the ceiling is more than 7. O The data suggest that the population mean time that it takes for bananas to spoil if they are hung from the ceiling is not significantly more than 7 at o: = 0.01 , so there is statistically insignificant evidence to conclude that the population mean time that it takes for bananas to spoil if they are hung from the ceiling is more than 7. O The data suggest the population mean is not significantly more than 7 at a = 0.01, so there is statistically insignificant evidence to conclude that the population mean time that it takes for bananas to spoil if they are hung from the ceiling is equal to 7. 0 Question 2 v The average American consumes 94 liters of alcohol per year. Does the average college student consume less alcohol per year? A researcher surveyed 14 randomly selected college students and found that they averaged 77.8 liters of alcohol consumed per year with a standard deviation of 21 liters. What can be concluded at the the a = 0.05 level of significance? a. For this study, we should use b. The null and alternative hypotheses would be: c. The test statistic = (please show your answer to 3 decimal places.) d. The p-value = (Please show your answer to 4 decimal places.) e. The p-value is a: f. Based on this, we should the null hypothesis. g. Thus, the final conclusion is that O The data suggest the populaton mean is significantly less than 94 at o: = 0.05, so there is statistically significant evidence to conclude that the population mean amount of alcohol consumed by college students is less than 94 liters per year. Q The data suggest the population mean is not significantly less than 94 at a = 0.05, so there is statistically insignificant evidence to conclude that the population mean amount of alcohol consumed by college students is equal to 94 liters per year. Q The data suggest that the population mean amount of alcohol consumed by college students is not significantly less than 94 liters per year at a = 0.05, so there is statistically insignificant evidence to conclude that the population mean amount of alcohol consumed by college students is less than 94 liters per year. 0 Question 3 v The average number of accidents at controlled intersections per year is 5.2. Is this average less for intersections with cameras installed? The 69 randomly observed intersections with cameras installed had an average of 4.9 accidents per year and the standard deviation was 1.35. What can be concluded at the a = 0.10 level of significance? a. For this study, we should use b. The null and alternative hypotheses would be: c. The test statistic = (please show your answer to 3 decimal places.) d. The p-value = (Please show your answer to 4 decimal places.) e. The p-value is o: f. Based on this, we should the null hypothesis. g. Thus, the final conclusion is that O The data suggest that the population mean is not significantly less than 5.2 at a = 0.10, so there is statistically insignificant evidence to conclude that the population mean number of accidents per year at intersections with cameras installed is less than 5.2 accidents. O The data suggest that the populaton mean is significantly less than 5.2 at a = 0.10, so there is statistically significant evidence to conclude that the population mean number of accidents per year at intersections with cameras installed is less than 5.2 accidents. 0 The data suggest that the sample mean is not significantly less than 5.2 at oz = 0.10, so there is statistically insignificant evidence to conclude that the sample mean number of accidents per year at intersections with cameras installed is less than 4.9 accidents. h. Interpret the p-value in the context of the study. 0 If the population mean number of accidents per year at intersections with cameras installed is 5.2 and if another 69 intersections with cameras installed are observed then there would be a 14628795496 chance that the population mean number of accidents per year at intersections with cameras installed would be less than 5.2. Q There is a 14628795496 chance that the population mean number of accidents per year at intersections with cameras installed is less than 5.2. Q If the population mean number of accidents per year at intersections with cameras installed is 5.2 and if another 69 intersections with cameras installed are observed then there would be a 3.46287954% chance that the sample mean for these 69 intersections with cameras installed would be less than 4.9. Q If the population mean number of accidents per year at intersections with cameras installed is 5.2 and if another 69 intersections with cameras installed are observed then there would be a 3.46287954% chance that the sample mean for these 69 intersections with cameras installed would be less than 4.9. Q There is a 14628795496 chance of a Type I error. i. Interpret the level of significance in the context of the study. Q If the population population mean number of accidents per year at intersections with cameras installed is less than 5.2 and if another 69 intersections with cameras installed are observed then there would be a 10% chance that we would end up falsely concluding that the population mean number of accidents per year at intersections with cameras installed is equal to 5.2. Q There is a 10% chance that you will get in a car accident, so please wear a seat belt. Q If the population mean number of accidents per year at intersections with cameras installed is 5.2 and if another 69 intersections with cameras installed are observed then there would be a 10% chance that we would end up falsely concluding that the population mean number of accidents per year at intersections with cameras installed is less than 5.2. Q There is a 10% chance that the population mean number of accidents per year at intersections with cameras installed is less than 5.2. Question 4 Women are recommended to consume 1860 calories per day. You suspect that the average calorie intake is smaller for women at your college. The data for the 13 women who participated in the study is shown below: 1795, 1672, 1908, 1746, 1733, 1789, 1964, 2014, 1843, 1556, 1928, 1630, 1819 Assuming that the distribution is normal, what can be concluded at the a = 0.10 level of significance? a. For this study, we should use Select an answer b. The null and alternative hypotheses would be: Ho: ? Select an answer H1 : ? Select an answer c. The test statistic ? = (please show your answer to 3 decimal places.) d. The p-value = (Please show your answer to 4 decimal places.) e. The p-value is ? v a f. Based on this, we should Select an answer v the null hypothesis. g. Thus, the final conclusion is that ... The data suggest the population mean is not significantly less than 1860 at a = 0.10, so there is sufficient evidence to conclude that the population mean calorie intake for women at your college is equal to 1860. The data suggest that the population mean calorie intake for women at your college is not significantly less than 1860 at a = 0. 10, so there is insufficient evidence to conclude that the population mean calorie intake for women at your college is less than 1860. The data suggest the populaton mean is significantly less than 1860 at a = 0.10, so there is sufficient evidence to conclude that the population mean calorie intake for women at your college is less than 1860 h. Interpret the p-value in the context of the study. There is a 6.54681533% chance that the population mean calorie intake for women at your college is less than 1860. If the population mean calorie intake for women at your college is 1860 and if you survey another 13 women at your college, then there would be a 6.54681533% chance that the sample mean for these 13 women would be less than 1800. O There is a 6.54681533% chance of a Type | error. O If the population mean calorie intake for women at your college is 1860 and if you surveyQ There is a 6.54681533% chance of a Type I error. Q If the population mean calorie intake for women at your college is 1860 and if you survey another 13 women at your college, then there would be a 65468153396 chance that the population mean calorie intake for women at your college would be less than 1860. i. Interpret the level of significance in the context of the study. Q If the population mean calorie intake for women at your college is 1860 and if you survey another 13 women at your college, then there would be a 10% chance that we would end up falsely concuding that the population mean calorie intake for women at your college is less than 1860. Q There is a 10% chance that the population mean calorie intake for women at your college is less than 1860. Q There is a 10% chance that the women at your college are just eating too many desserts and will all gain the freshmen 15. Q If the population mean calorie intake for women at your college is less than 1860 and if you survey another 13 women at your college, then there would be a 10% chance that we would end up falsely concuding that the population mean calorie intake for women at your college is equal to 1860. Question 5 Test the claim that the mean GPA of night students is significantly different than 2.7 at the 0.01 significance level. The null and alternative hypothesis would be: Ho:p = 0.675 Ho :p 2 0.675 Ho:u 2.7 Ho :p 2.7 H1:u # 2.7 Hi:u 0.675 O O The test is: two-tailed right-tailed left-tailed Based on a sample of 65 people, the sample mean GPA was 2.68 with a standard deviation of 0.03 The p-value is: (to 2 decimals) Based on this we: O Fail to reject the null hypothesis O Reject the null hypothesis0 Question 6 v You wish to test the following claim (Ha) at a significance level of a = 0.001. Hoip = 73.4 Hans > 73.4 You believe the population is normally distributed, but you do not know the standard deviation. You obtain a sample of size n : 19 with mean M : 77.9 and a standard deviation of SD : 17.8. What is the p-value for this sample? (Report answer accurate to four decimal places.) p-value = The p-value is... O less than (or equal to) a: O greater than a: This p-value leads to a decision to... O reject the null O accept the null O fail to reject the null As such, the final conclusion is that... Q There is sufficient evidence to warrant rejection of the claim that the population mean is greater than 73.4. C) There is not sufficient evidence to warrant rejection of the claim that the population mean is greater than 73.4. O The sample data support the claim that the population mean is greater than 73.4. 0 There is not sufficient sample evidence to support the claim that the population mean is greater than 73.4. Question 1 You are conducting a study to see if the proportion of voters who prefer the Democratic candidate is significantly smaller than 58% at a level of significance of a = 0.10. According to your sample, 38 out of 74 potential voters prefer the Democratic candidate. a. For this study, we should use Select an answer b. The null and alternative hypotheses would be: Ho: ? Select an answer (please enter a decimal) H1: ? Select an answer (Please enter a decimal) C. The test statistic |? v = (please show your answer to 3 decimal places.) d. The p-value = (Please show your answer to 4 decimal places.) e. The p-value is ? v a f. Based on this, we should Select an answer | the null hypothesis. g. Thus, the final conclusion is that ... The data suggest the population proportion is not significantly smaller than 58% at a = 0.10, so there is sufficient evidence to conclude that the proportion of voters who prefer the Democratic candidate is equal to 58% The data suggest the population proportion is not significantly smaller than 58% at a = 0. 10, so there is not sufficient evidence to conclude that the proportion of voters who prefer the Democratic candidate is smaller than 58%. The data suggest the populaton proportion is significantly smaller than 58% at a = 0.10, so there is sufficient evidence to conclude that the proportion of voters who prefer the Democratic candidate is smaller than 58% h. Interpret the p-value in the context of the study. There is a 12.33% chance that fewer than 58% of all voters prefer the Democratic candidate. There is a 58% chance of a Type | error. If the population proportion of voters who prefer the Democratic candidate is 58% and if another 74 voters are surveyed then there would be a 12.33% chance fewer than 52% of the 74 voters surveyed prefer the Democratic candidate. O If the sample proportion of voters who prefer the Democratic candidate is 52% and if another 74 voters are surveyed then there would be a 12.33% chance of concluding that fewer than 58% of all voters surveyed prefer the Democratic candidate. i. Interpret the level of significance in the context of the study. There is a 10% chance that the proportion of voters who prefer the Democratic candidate is smaller than 58%.O The data suggest the population proportion is not significantly smaller than 58% at 0: = 0.10, so there is not sufficient evidence to conclude that the proportion of voters who prefer the Democratic candidate is smaller than 58%. O The data suggest the populaton proportion is significantly smaller than 58% at a = 0.10, so there is sufficient evidence to conclude that the proportion of voters who prefer the Democratic candidate is smaller than 58% h. Interpret the p-value in the context of the study. 0 There is a 12.33% chance that fewer than 58% of all voters prefer the Democratic candidate. 0 There is a 58% chance of a Type I error. 0 If the population proportion of voters who prefer the Democratic candidate is 58% and if another 74 voters are surveyed then there would be a 12.33% chance fewer than 52% of the 74 voters surveyed prefer the Democratic candidate. 0 If the sample proportion of voters who prefer the Democratic candidate is 52% and if another 74 voters are surveyed then there would be a 12.33% chance of concluding that fewer than 58% of all voters surveyed prefer the Democratic candidate. i. Interpret the level of significance in the context of the study. 0 There is a 10% chance that the proportion of voters who prefer the Democratic candidate is smaller than 58%. C) If the proportion of voters who prefer the Democratic candidate is smaller than 58% and if another 74 voters are surveyed then there would be a 10% chance that we would end up falsely concluding that the proportion of voters who prefer the Democratic candidate is equal to 58%. Q There is a 10% chance that the earth is flat and we never actually sent a man to the moon. 0 If the population proportion of voters who prefer the Democratic candidate is 58% and if another 74 voters are surveyed then there would be a 10% chance that we would end up falsely concluding that the proportion of voters who prefer the Democratic candidate is smaller than 58% 0 Question 2 v The recidivism rate for convicted sex offenders is 16%. A warden suspects that this percent is higher if the sex offender is also a drug addict. Of the 383 convicted sex offenders who were also drug addicts, 73 of them became repeat offenders. What can be concluded at the a = 0.10 level of significance? a. For this study. we should b. The null and alternative hypotheses would be: Ho: (please enter a decimal) H11 (Please enter a decimal) c. The test statistic = (please show your answer to 3 decimal places.) d. The p-value = (Please show your answer to 4 decimal places.) e. The p-value is o: f. Based on this, we should the null hypothesis. g. Thus, the final conclusion is that O The data suggest the population proportion is not significantly higher than 16% at a = 0.10, so there is statistically insignificant evidence to conclude that the population proportion of convicted sex offender drug addicts who become repeat offenders is higher than 16%. O The data suggest the populaton proportion is significantly higher than 16% at a = 0.10, so there is statistically significant evidence to conclude that the population proportion of convicted sex offender drug addicts who become repeat offenders is higher than 16%. O The data suggest the population proportion is not significantly higher than 16% at a = 0.10, so there is statistically significant evidence to conclude that the population proportion of convicted sex offender drug addicts who become repeat offenders is equal to 16%. h. Interpret the p-value in the context of the study. 0 If the sample proportion of convicted sex offender drug addicts who become repeat offenders is 19% and if another 383 convicted sex offender drug addicts are observed then there would be a 5.12% chance of concluding that more than 16% of all convicted sex offender drug addicts become repeat offenders. Q There is a 5.12% chance that more than 16% of all convicted sex offender drug addicts become repeat offenders. Q If the population proportion of convicted sex offender drug addicts who become repeat offenders is 16% and if another 383 convicted sex offender drug addicts are surveyed then there would be a 5.12% chance that more than 19% of the 383 convicted sex offender drug addicts in the study will become repeat offenders. Q There is a 5.12% chance of a Type I error. i. Interpret the level of significance in the context of the study. /'\\-r.l l.- .- r -. I (r I I II-. I I there 15 statistically inSIgnmcant evmehce to conctuoe that the population proportion or convicted sex offender drug addicts who become repeat offenders is higher than 16%. O The data suggest the populaton proportion is significantly higher than 16% at a: = 0.10, so there is statistically significant evidence to conclude that the population proportion of convicted sex offender drug addicts who become repeat offenders is higher than 16%. O The data suggest the population proportion is not significantly higher than 16% at a = 0.10, so there is statistically significant evidence to conclude that the population proportion of convicted sex offender drug addicts who become repeat offenders is equal to 16%. h. Interpret the p-value in the context of the study. 0 If the sample proportion of convicted sex offender drug addicts who become repeat offenders is 19% and if another 383 convicted sex offender drug addicts are observed then there would be a 5.12% chance of concluding that more than 16% of all convicted sex offender drug addicts become repeat offenders. C) There is a 5.12% chance that more than 16% of all convicted sex offender drug addicts become repeat offenders. Q If the population proportion of convicted sex offender drug addicts who become repeat offenders is 16% and if another 383 convicted sex offender drug addicts are surveyed then there would be a 5.12% chance that more than 19% of the 383 convicted sex offender drug addicts in the study will become repeat offenders. C) There is a 5.12% chance of a Type I error. i. Interpret the level of significance in the context of the study. 0 If the population proportion of convicted sex offender drug addicts who become repeat offenders is 16% and if another 383 convicted sex offender drug addicts are observed, then there would be a 10% chance that we would end up falsely concluding that the proportion of all convicted sex offender drug addicts who become repeat offenders is higher than 16%. Q If the population proportion of convicted sex offender drug addicts who become repeat offenders is higher than 16% and if another 383 convicted sex offender drug addicts are observed then there would be a 10% chance that we would end up falsely concluding that the proportion of all convicted sex offender drug addicts who become repeat offenders is equal to 16%. Q There is a 10% chance that the proportion of all convicted sex offender drug addicts who become repeat offenders is higher than 16%. Q There is a 10% chance that Lizard People aka "Reptilians" are running the world. 0 Question 3 v You are conducting a study to see if the accuracy rate for fingerprint identification is significantly Less than 0.85. You use a significance level of a = 0.05. ngp= 0.85 H1:p Only about 11% of all people can wiggle their ears. Is this percent different for millionaires? Of the 396 millionaires surveyed, 59 could wiggle their ears. What can be concluded at the a = 0.01 level of significance? a. For this study, we should use b. The null and alternative hypotheses would be: H0: (Please enter a decimal) H1 1 (Please enter a decimal) c. The test statistic = (please show your answer to 3 decimal places.) d. The p-value = (Please show your answer to 3 decimal places.) e. The p-value is a f. Based on this, we should the null hypothesis. g. Thus, the final conclusion is that O The data suggest the population proportion is not significantly different from 11% at a = 0.01, so there is statistically significant evidence to conclude that the population proportion of millionaires who can wiggle their ears is equal to 11%. O The data suggest the populaton proportion is significantly different from 11% at a = 0.01, so there is statistically significant evidence to conclude that the population proportion of millionaires who can wiggle their ears is different from 11%. O The data suggest the population proportion is not significantly different from 11% at as = 0.01, so there is statistically insignificant evidence to conclude that the population proportion of millionaires who can wiggle their ears is different from 11%. . Question 5 Test the claim that the proportion of people who own cats is larger than 80% at the 0.05 significance level. The null and alternative hypothesis would be: Ho:u 20.8 Ho:p 0.8 H1 :u> 0.8 H1 :u #0.8 H1 :p You wish to test the following claim (Ha) at a significance level of a = 0.10. Ho:p = 0.81 Ha:p