0 Question 25 v > A fitness center is interested in finding a 90% confidence interval for the mean number of days per week that Americans who are members of a fitness club go to their fitness center. Records of 277 members were looked at and their mean number of visits per week was 2.3 and the standard deviation was 1.8. Round answers to 3 decimal places where possible. a. To compute the confidence interval use a distribution. b. With 90% confidence the population mean number of visits per week is between [:J and C] visits. c. If many groups of 277 randomly selected members are studied, then a different confidence interval would be produced from each group. About [3 percent of these confidence intervals will contain the true population mean number of visits per week and about C] percent will not contain the true population mean number of visits per week. Hint: Hints L7' Video 37' [+] Submit Question 0 Question 22 v ' > ' B 6 pts '0 1 8 99 (D Details The amount of coffee that people drink per day is normally distributed with a mean of 16 ounces and a standard deviation of 6 ounces. 12 randomly selected people are surveyed. Round all answers to 4 decimal places where possible. c. What is the probability that one randomly selected person drinks between 14.5 and 17 ounces of coffee per day? d. For the 12 people, find the probability that the average coffee consumption is between 14.5 and 17 ounces of coffee per day. . For part d), is the assumption that the distribution is normal necessary? 0 YesO No . Find the IQR for the average of 12 coffee drinkers. Q1 = ounces :] Q3 = [j ounces :l IQR: ounces -!D Hint: Some Helpful Videos: 0 Finding the Sampling Distribution 8'7 [+] - Finding a Probability Using the Central Limit Theorem 5' [+] - Finding Value Given a Probability Using the Central Limit Theorem @ [+] o The Central Limit Theorem For Sums 5' [+] Hint L3 Submit Question