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0 Use partial derivatives to locate critical points for a function of two variables. Find the values of 33, y and ,2: that correspond to

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0 Use partial derivatives to locate critical points for a function of two variables. Find the values of 33, y and ,2: that correspond to the critical point of the function: z: f(a:,y) : 2332+3az+ 1yl3y2 2333; Enter your answer as a decimal number, or a calculation (like 22/7). places) y_ (and t4decimal places) places)

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