0.08 m s of air at 1.0 bar and 305 K with 60 % relative humidity and the wet bulb temperature of 299 K, is to be cooled to 275 K. Calculate: (i) The total mass of moisture condensed. (ii) The amount of heat to be removed. Additional information: Evaporation heat of water (273 K): Specific heat capacity of water vapour (273-305K): Specific heat capacity of dry air (273-305 K): Saturated pressure of water vapour at 305 K: Saturated pressure of water vapour at 275 K: 2500 kJ kg. 1.9 kJ kg K. 1.0 kJ kg K. 0.0469 bar. 0.00601 bar.