021 (part 1 of 4) 10.0 points A ball is thrown horizontally from the top of a building 38.2 m high. The ball strikes the ground at a point 75.9 m from the base of the building. The acceleration of gravity is 9.8 m/:". Find the time the ball is in motion. Answer in units of s. 022 (part 2 of 4) 10.0 points Find the initial velocity of the ball. Answer in units of m/s. 023 (part 3 of 4) 10.0 points Find the r component of its velocity just be- fore it strikes the ground. Answer in units of m/s. 024 (part 4 of 4) 10.0 points Find the y component of its velocity just be- fore it strikes the ground. Answer in units of m/s. 025 (part 1 of 4) 10.0 points Denote the initial speed of a cannon ball fired from a battleship as vo. When the initial projectile angle is 45" with respect to the horizontal, it gives a maximum range It... . . + 45 R/2 R The time of flight tmaz of the cannonball for this maximum range R is given by 1. tras = 2 g 29113 1 2. tmar 3. tmar =1 4. tmar 5. tmar = B. tmar 7. tmax V 8. tmar 9. tmar 10. tmor = 4 026 (part 2 of 4) 10.0 points The maximum height Amar of the cannonball is given by 1. hmas = 4 2. hmaz 3. hmaz = V A. hmaz 5. hmaz 6. hmaz7. hmaz = 2 9. hmaz 10. hmaz = V3 027 (part 3 of 4) 10.0 points The speed up, of the cannonball at its max- imum height is given by 1. Vmas = 2 40 2. Uhman 3. Uhmas = V2 vo 4. VAmar 2 5. Umax - UI B. Ullmar 7. Uhmax 8. Uhmas 9. Uhmez 2-911 10. Uhmez 028 (part 4 of 4) 10.0 points At a new angle, 0 , the new range is given by R = The corresponding angle, O', which is greater than 45", is given by 1. 70