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( 1 0 pt ) In the textbook RSA scheme which is deterministic, the system parameter is as follows: N = 3 3 , and
pt In the textbook RSA scheme which is deterministic, the system parameter is as follows: and Note that and modN
a Compute a secret key
pt The schnorr signature scheme is given as follows: Setup: and
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ITE Spring : Final Examination
If then compute and a signature. And then perform to verify the signature with Note that let
If adversary can forge the schnorr signature scheme, which intractable problem is broken? Using the above setting, break the intractable assumption.
pt We call as a Blum integer if such that pmod and qmod For a given if adversary can compute then we can factor as following. Note that with a half probability, called a quadratic residue is a square of a certain number in
We choose a random and compute And then we give to adversary Then adversary returns a square root of There are square roots of and for two numbers or
For we choose Assume that adversary receives List all square roots of And show that or by computing Using factor
pt Write a GQ signature scheme. Using the random oracle model, you can compute where in the GQ Assume that returns a bit number and where is a bit. Using the previous problem, you can break the factoring problem of if adversary can forge a signature in the GQ when is a blum integer. Explain how to factor
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