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1 1 l . .3 I Z/ I :r' (1.1 : f Fir. _1 ( J V27? _1 This Integral shows that the probability of

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1 1 l . .3 I Z/ I :r' (1.1" : f Fir. _1 ( J V27? _1 This Integral shows that the probability of a measure being between plus and minus a standard deviation, is approximately 68%. Find fl] T2(:I:)da: m I And compare with the right result: I = 0.6826 ..l

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