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1. [-/1 Points] DETAILS LARCALC11 14.4.004.MI. Find the mass of the lamina described by the inequalities, given that its density is p(x, y) = xy.
1. [-/1 Points] DETAILS LARCALC11 14.4.004.MI. Find the mass of the lamina described by the inequalities, given that its density is p(x, y) = xy. O S X 5 4, 0 Sys 16 - x2 Need Help? Read It Watch It Master It Submit Answer 2. [-/1 Points] DETAILS LARCALC11 14.4.007. Find the mass and center of mass of the lamina corresponding to the region R for each density. R: square with vertices (0, 0), (a, 0), (0, a), (a, a) (a ) p =k m = ( x , y ) = (b ) p = ky m = ( x , y ) = (c) p = kx m = ( x , y ) =3. [-/1 Points] DETAILS LARCALC11 14.4.022. MY NOTES ASK YOUR TEACHER Find the mass and center of mass of the lamina bounded by the graphs of the equations for the given density. PRACTICE y = Cos _X y = 0 X = 0 X = 4 0 = ky m : ( x, y ) = Need Help? Read It Submit Answer 4. [-/1 Points] DETAILS LARCALC11 14.4.027. MY NOTES ASK YOUR TEACHER PRACTICE ANOTH Use a computer algebra system to find the mass and center of mass of the lamina bounded by the graphs of the equations for the given density. (Round your answers to two decimal places.) r = 7 cos 30 6- p = k m = ( x, y ) = () Need Help? Read It Watch It C O S @ 6 3 4 5 E R Wlar - C webassign.net/web/Student/Assignment-Responses/last?dep=31665 M Gmail YouTube Maps [-/1 Points] DETAILS LARCALC11 14.5.003. Find the area of the surface given by z = f(x, y) that lies above the region R. f ( x, y ) = 4x+ 4y R: triangle with vertices (0, 0), (4, 0), (0, 4) Need Help? Read It Watch It Submit Answer [-/1 Points] DETAILS LARCALC11 14.5.009. Find the area of the surface given by z = f(x, y) that lies above the region R. f ( x, y ) = 3+ 4x3/2 R: rectangle with vertices (0, 0), (0, 2), (6, 2), (6, 0) 1 84OF Partly sunny Q Search DLOCourse Hero X Hill Content x VA 14.5 Homework- S X Plan & Schedule Cc X Make C webassign.net/web/Student/Assignment-Responses/last?dep=31665155 M Gmail YouTube Maps -/1 Points] DETAILS LARCALC11 14.5.017. Find the area of the surface. The portion of the plane z = 18 - 3x - 2y in the first octant Need Help? Read It Watch It Submit Answer [-/1 Points] DETAILS LARCALC11 14.5.027. Set up a double integral that represents the area of the surface given by z = f(x, y) that lies above the region R. f ( x , y ) = exy R = { ( x, y) : 0
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