1. [-/1 Points] DETAILS UMASSA2L1 13.P.001. A uniform volume distribution of charge has radius R and total charge Q. A point charge -q is released from rest at point b, which is a distance 3R from the center of the distribution. O When the point charge reaches a, which of the following is true regarding the potential energy, U? OU. = -Ub O U. = _ -20b O U. = - -3Ub 2 OU. = - - 9ub OU. = Ub OU = ZUb 3 O Ua O UA = _ O none of the above O cannot be determined Submit Answer 2. [-/1 Points] DETAILS UMASSA2L1 13.P.007. Which of the following charge distributions has the lowest electric potential at the origin? 3 +Q +Q HO +Q la O Submit Answer3. [-/1 Points] DETAILS UMASSA2L1 13.P.008. Two point charges are fixed on the x-axis. A positive charge moves from point P to the origin along the different paths shown in the diagram below. P For which path would you do the most work? -Select v Submit Answer 4. [-/1 Points] DETAILS OSUNIPHYS1 24.3.P.051. (a) What is the potential differance (in V) between two points situated 19 cm and 38 cm from a 8.0 pC point charge? (Enter the magnitude.} W (b} To what location should the point at 38 cm be moved to increase this potential difference by a factor of two? (O 25.3 cm from the 8.0 pC point charge (O 25.3 cm from the 8.0 pC point charge 0.253 cm from the 8.0 pC point charge O infinity Additional Materials [ Reading Submit Answer MY NOTES ASK YOUR TEACHER PRACTICE ANOTHER 5. [-/1 Points] DETAILS OSUNIPHYS1 24.3.WA.015. In nuclear fission, 2 nucleus splits roughly in half. (a) What is the electric potential 6.24 x 10714 m from a fragment that has 84 protons in it? v electric potential energy in MeV of a similarly charged fragment at this distance? Mev (b) What is the Additional Materials. [ Reading Submit Answer MY NOTES ASK YOUR TEACHER PRACTICE ANOTHER 6. [-/1Points] | DETAILS | OSUNIPHYS124.3.WA.017. In one of the classic nuclear physics experiments at the beginning of the 20" century, an alpha particle was accelerated towards a gold nucleus and its path was substantially deflected by the Coulomb interaction. If the initial kinetic energy of the doubly charged alpha nucleus was 5.98 MeV, how close to the gold nucleus (79 protons) could it come before being turned around? m Additional Materials. 3 Reading 'Submit Answer ASK YOUR TEACHER PRACTICE ANOTHER 7. [-/2 Points] OSUNIPHYS1 24.3.WA.020. Three point charges ,, @, and g, are situated at three comers of a rectangle as shown in the diagram below. Here g = +8.00 yC, g, = =8.00 kC, g3 = +3.00 C, @ 7 O 250em 5.00cm Y % the electric potential at the free corner where there is no charge? v (2) What (b) What charge should be placed at the free corner for the electric potential at the center of the rectangle to be zero? Include the sign of the value in your answer. ue Additional Materials. (Reading 8. [-/1 Points] DETAILS 'OSUNIPHYS1 24.3.WA.023.TUTORIAL. MY NOTES ASK YOUR TEACHER PRACTICE ANOTHER Acharge g, = +1.52 jC is at a distance d = 1.13 m from a second charge g, = =5.77 iC. () Find the electric potential at a point A between the two charges that is d/4 from g,. Note that the location A in the diagram above is not to scale. v (b) Find a point between the two charges on the horizontal line where the electric potential is zero. (Enter your answer as measured from q,.) m Additional Materials (Reading @ Tutorial Submit Answier, 9. [-/2Points] | DETAILS | OSUNIPHYS124.3.WA.033. MY NOTES ASK YOUR TEACHER PRACTICE ANOTHER The radius of a solid conducting sphere is R = 14.0 cm and it has a uniformly distributed charge of 30.5 nC on its surface. The center of the sphere is at the origin of the xy coordinate system. The locations A, B, and C are at (~R/3, 0) cm, (R, 0) cm, and (3R, 0) cm, respectively. Determine the potential difference V, Vg and Vg V. Note that the diagram is not to scale. (b) Vg Additional Materials [ Reading, 'Submit Answer, 10. [-/2 Points] OSUNIPHYS1 24.5.P.059. A very large sheet of insulating material has had electrons removed from it to yield a surface charge density of +2.00 nC;'mz' (a) As the distance from the sheet increases, does the potential increase or decrease? O increase O decrease Can you explain why without any calculations? The electric field points in the direction of decreasing potential while pointing towards negative charges and away from positive charges. The electric field points in the direction of decreasing potential while pointing away from negative charges and towards positive charges. The electric field points in the direction of increasing potential while pointing towards negative charges and away from positive charges. O The electric field points in the direction of increasing potential while peinting away from negative charges and towards positive charges. Does the location of your reference point matter? (b) What is the shape of the equipotential surfaces? O planes perpendicular to the sheet O spheres whose centers do not lie on the sheet O spheres whose centers lie on the sheet O planes parallel to the sheet (c) What is the spacing (in m) between surfaces that differ by 7.00 V? m Additional Materials L Reading Submit Answer 11. [-/1 Points] OSUNIPHYS1 24.5.P.063. Two parallel plates 15 cm on a side are given equal and opposite charges of magnitude 5.5 x 107 C. The plates are 3.5 mm apart. What is the potential difference between the plates (in V)7 (Enter the magnitude.) vV Additional Materials L Reading Submit Answer 12. [-/1 Points] DETAILS OSUNIPHYS1 24.5.P.065. Concentric conducting spherical shells carry charges Q and -Q, respectively. The inner shell has negligible thickness. What is the potential difference between the shells? (Use the following as necessary: k, Q, a, and b.) b C V(b) - V(a) = Additional Materials Reading Submit Answer13. [-/2 Points] DETAILS OSUNIPHYS1 24.5.WA.049. The equipotential lines in a region of electric field are shown in the diagram below. For each path indicated below, what is the work done by the electric field in moving a charge q = +7.5 x 10" C along that path? Here V, = +200 V. 3Vo D 2VO Vo -V A OV -2V B -3V (a) from A to B WAR = (b) from A to C WAC = (c) from A to D WAD = (d) from D to C WDC = Additional Materials Reading Submit Answer14. [-/1.5 Points] - OSUNIPHYS1 24.6.P.070. A simple and commen technigue for accelerating electrons is shown in the figure below, where there is a uniform electric field between two plates. | Electrons are released, usually from a hot filament, near the negative plate, and there is a small hole in the positive plate that allows the electrons to continue moving. (a) Calculate the acceleration (in mf52] of the electron if the field strength is 8.20 x 10% N/C. (Enter the magnitude.) r'rl,r's2 (b} Explain why the electron will not be pulled back to the positive plate once it moves through the hole. O The force of gravity is too strong. O There is no field outside the plates. O The other side of the positive plate also has a negative charge. Additional Materials LA Reading Submit Answer 15. [-/1.5 Points] DETAILS OSUNIPHYS1 24.4.WA.039. MY NOTES ASKYO In the diagram below, each division on the horizontal axis (the displacement s) is 0.10 m while each division on the vertical axis (the electric potential V) is 1.0 V. What is the electric field component along the displacement axis s in each of the regions specified below? Include the sign of the value in your answer. vv) 6.0 4.0 2.0 0.20 040 0.60 0.80 s (m) (a) from 0.0 m t0 0.30 m v/m (b) from 0.30 m t0 0.0 m v/m (