1. [-10.06 Points] DETAILS SCALCE'I'B 11.1.AE.DDZ. 01100 SL1 bmissioms Used MY NOTES ASK YOUR TEACHER Example Video Exampleim Find a formula for the general tem of the sequence assuming that the pattern of the rst few terms continues. 5 _6 7 _s 9 3' 9'27' 81'243"" Solulicln We are given the following. 5 6 7 8 9 a = a = 7 a = a = 7 a = 1 3 2 9 3 27 4 81 5 243 Notice that the numemtors of these fractions start with 5 and increase by whenever we go to the next term. 111e second term has numerator 6, the third ten'n has numerator 7; in general, the nth term will have numerator . The denominators are powers of , so a" has denominator The signs of the ten'ns are alternately positive and negative so we need to multiply by a power of 71. Here we want to start with a positive tem and so we use (71)" _ 1 or [7])" + 1. Therefore, we have the following. an=(l.)\"_l-( ) Need Help? 4. [40.06 Points] DETAILS SEALEETB 11.1.019. 01100 Submissions Used Find a formula for the general term an of the sequence, assuming that the pattern of the rst few terms continues. (Assume that :1 begins with 1.) {3; 2. ii 15, ...} 3 9 2? a =i:i n