1. [-/1.33 Points] DETAILS PSE6 4.CQ.004. MY NOTES ASK YOUR TEACHER A baseball is thrown with an initial velocity of (22 i + 16 j) m/s. Neglect the effect of air resistance. (a) When it reaches the top of its trajectory, what is its velocity? im/'s b) When it reaches the top of its trajectory, what is its acceleration? lim/'s2. [-/1.33 Points] DETAILS SERPSE7 4.P.002. A golf ball is hit off a tee at the edge of a diff. Its x and y coordinates as functions of time are given by the following expressions. * = [15.0 m/s) y = (5.80 m/s)t - (4.90 m/s ) (a] Immediately after the golf ball is hit, In which of the following directions is the golf ball moving? O (b) Write a vector expression for the ball's position as a function of time, using the unit vectors i and j. (Use the following as necessary: t.) (c) By taking derivatives, obtain an expression for the velocity vector v as a function of time. (Use the following as necessary: t.) m/'s ji + ( m/'s ) i (d) By taking derivatives, obtain an expression for the acceleration vector a as a function of time. (Use the following as nemscary: t.) m/'s' ) 1+ m/s )i (e) Next use unit vector notation to write an expression for the position of the golf ball at t = 3.20 s. (3.20 5) - ( mji+ (f) Write an expression for the velocity at this time. W(3.205) - m/sji+ (L I m/s ji (g) Write an expression for the acceleration at this time. a( 3.20 5) -[ Im/s )1+ 0 m/s )13. [-/1.33 Points] DETAILS SERPSE7 4.P.004. The coordinates of an object moving in the xy plane vary with time according to the following equations. t is in seconds and @ has units of seconds -1. x = -(2.40 m) sin(wt) y = (4.00 m) - (2.40 m) cos(wt) (=) Determine the components of velocity and components of acceleration at t = 0. (Use w as appropriate.) 10 m/'s 1) m/s2 (b) Write expressions for the position vector, the velocity vector, and the acceleration vector at any time t > 0. (Use @ and t as appropriate.) m a m/s2 (c) Describe the path of the object on an xy graph. This answer has not been graded yet.4. [-/1.33 Points] DETAILS SERPSE7 4.P.005.SOLN. MY NOTES ASK YOUR TEACHER A fish swimming in a horizontal plane has velocity v, = (4.00 i - 1.00 j) m/s at a point in the ocean where the position relative to a certain rock is r, = (-10.0 i - 4.00 j) m. After the fish swims with constant acceleration for 24.0 s, its velocity is v = (22.0 i - 5.00 j) m/s. O (a) What are the components of the acceleration? m/s2 m/s (b) what is the direction of the acceleration with respect to unit vector i? + (counterclockwise from the +x-axis is positive) (c) If the fish maintains constant acceleration, where is it at t = 32.0 s? * = m y = m In what direction is it moving? (counterclockwise from the +x-axis is positive)