1. [5 pts] A 0.64 m thick solidified metal exits from the mold in a continuous casting. The metal has 1.36 W/(mC) thermal conductivity, 0.55 J/(KgC) specific heat, 306 J/Kg solidification latent heat, and 1,410C melting point. The heat transfer coefficient between melt and mold is 1.7 W/m2C, and room temperature is 20C. If the down feed rate is reduced by 20%, what would be the solidified metal thickness (in m) at mold exit? Use the parametric relationship below. 1.0 H-0.1/ 0.2/ 0.3, 044 Se 0.8 0.6 0.4 0.2 0.2 0.4 0.6 Y* 0.8 05 0.7 1.0 3. (4 points) In continuous casting with a 6 mm/sec down feed rate, it produces a solidified metal thickness of 0.4 m at the mold exit where the heat transfer coefficient is 1.7 W/m2C. The thermal conductivity of the solid metal is 1.36 W/(mC), specific heat of solid metal 0.55 J/(KgC), solidification latent heat 306 J/Kg, metal melting point 1,410C, and room temperature 20C. If the down feed rate is reduced by half, what would be the solidified metal thickness (in m) at mold exit? (a) 0.22, (b) 0.44, (c) 0.52, (d) 0.64, (e) 0.77, (f) 0.82. 1.0 S* 0.8 0.6 0.4 0.2 H = 0.1 0.2 0.2/ 0.4 0.3 0.6 Y* 0.4 0.5 0.8 0.7 1.0 3. (d). H* = = 0.40, S* h8_1.7(0.4) 1.36 = 0.50 k From the figure, Y*=0.32. If feed rate is reduced by half, Y* doubles to 0.64. 1.78 Therefore the new S* = 0.80 S*=0.8= 8 = 0.64 m 1.36 H C(Tm-T) = 306 0.55(1410-20) = =