'1' ' ' "" '7 " ' ' "' ' ""J' Project: Part 4 Hypothesis Tests Assignment For this part of the project and based on your sample, you will conduct a hypothesis test with a: = 0.05 to test two of the claims of the above article. Using the same excel sheet as Part 3, answer the following in the \"Module 6\" tab: 0 Claim: the average age of online students is 32 years old. Can you prove it is not? What is the null hypothesis? What is the alternative hypothesis? What distribution should be used? What is the test statistic? What is the p-value? What is the conclusion? How do we interpret the results, in context of our study? 0 Claim: the proportion of males in online classes is 35%. Can you prove it is not? What is the null hypothesis? What is the alternative hypothesis? What distribution should be used? What is the test statistic? What is the p-value? What is the conclusion? How do we interpret the results, in context of our study? OOOOOOO OOOOOOO BEFORE BEGINNING, PLEASE VIEW MY VIDEO TUTORIAL FOR THIS PROJECT - THE LINK IS FOUND IN OUR WEEK 5 ANNOUNCEMENTS Review your ALEKS e-text sections 8.2, 8.3 Note: The goal of the project is to practice making a confidence interval for a mean and proportion with real data. Do not worry about failed assumptions tests and do not make corrections for small sample size. Use primary methods described in text and used on homework. Age Gender Use a 95% Confidence Interval for Average Age of Online College Students: 20 W POINT DISTRIBUTION 26 F Point Values Points Earned Sample Mean: 27.90 24 F Sample St. Dev: 9.09 25 F Sample Size: 22 49 F 24 F 2 Distribution: T-Distribution (Choose from drop-down menu) 22 M 26 M 2 Critical Value: 2.0796138 2.08 37 M 32 M N Margin of Error: 4.0303 25 N Lower Bound: 23.87 23 M Upper Bound: 31.93 44 M 28 M State a Therefore, we have a 95% confidence that the real population mean is between 23.8697 and 31.9303. In relation 24 F 2 conclusion: to this, around 95% of these confidence intervals will contain the genuine population mean, and approximately 19 M 50 M 95% Confidence Interval for Proportion of Male Online College Students: 20 M 28 M Sample Size: 22 21 M N - - Number of Males: 15 27 M Male Proportion: 0.6818181 Female Proportion 1.2956 20 F N Distribution: T-Distribution (Choose from drop-down menu) N Critical Value: 2.079613 Margin of Error: .2065 - - N Lower Bound: 0.4753 Upper Bound: 0.8883 Therefore, we have a 95% confidence level that the genuine population percentage is between 0.4753 and 2 State a 0.8883. Regarding this, around 95% of these confidence intervals will contain the genuine population conclusion: percentage, and approximately 5% will not. 25 0 = 0%For the following two hypothesis tests, use the alpha = .05 POINT DISTRIBUTION Point Values Points Earned Claim: The average age of online students is 32 years old. Can you prove it is not? Ho: N - Ha: Sample mean: 27.9 Sample St. Dev: 9.09 N Distribution: (Choose from drop-down menu) Test Statistic: - NN p-value: Interpret p-value: (Choose from drop-down menu) N State a conclusion: Claim: The proportion of males in online classes is 35%. Can you prove it is not? Ho: N - Ha: Sample Proportion Males 0.681818181818182 Sample Proportion Females 1.2956 N Distribution: (Choose from drop-down menu) Test Statistic: - NW p-value: Interpret p-value: (Choose from drop-down menu) N State a conclusion: 25 0 = 0%