1" (7x -3)3 Let f(:I) = V9x3 + 10 If we use the method of logarithmic differentiation to find f'(x). we obtain f'(x) in the form 1 (71 - 3)3 B(I) C(I) f'(x) = A(=) + 71 - 3 + V9x2+ 10 9:x3 + 10 where A(x). B(x) and C(x) are functions of c. Find them, Answer: A(I) B(z) and C(2)