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1. A ball is launched horizontally from the top of a cliff with an initial velocity of 20 m/s. The trajectory of the ball is
1. A ball is launched horizontally from the top of a cliff with an initial velocity of 20 m/s. The trajectory of the ball is shown below. Express your understanding of the change in velocity of a projectile by filling in the blanks next to each ball position. Yx = 20 m/s t-0 sec, Vy=0 m/s + t= 1 sec. Y.= 1=2 sec. Yu 1=3 sec, Yu NOTE: This vector diagram is depicting velocity vectors, not force or acceleration vectors. 1-4 sec, Yo The ball in the diagram above strikes the ground after 4 seconds. 2. How high was the cliff the ball was thrown from? 3. How far from the base of the cliff will the ball land? 4. If the ball was thrown at a different initial velocity and landed 26.3 meters from the base of a 19.3 meter high cliff, with what initial velocity was it thrown? *This is a multi-step
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