Answered step by step
Verified Expert Solution
Link Copied!

Question

1 Approved Answer

1. A horizontal power line carries a current of 7480 A from south to north. Earth's magnetic field (45.2 uT) is directed toward the north

1.

image text in transcribedimage text in transcribedimage text in transcribedimage text in transcribedimage text in transcribedimage text in transcribedimage text in transcribedimage text in transcribedimage text in transcribedimage text in transcribedimage text in transcribedimage text in transcribed
A horizontal power line carries a current of 7480 A from south to north. Earth's magnetic field (45.2 uT) is directed toward the north and is inclined downward at 55.0 to the horizontal. Find the (a) magnitude and (b) direction of the magnetic force on 150 m of the line due to Earth's field. (a) Number i Units (b)O A from south to north. Earth's magne ntal. Find the (a) magnitude and (b) dire Units V This answer has no units (degrees) m kg S m/s m/s^2 N N/m kg.m/s or N.s N/m^2 or Pa kg/m^3 m/s^3 timesA horizontal power line carries a current of 7480 and is inclined downward at 55.0 to the horizon due to Earth's field. (a) Number (b) Sal to the east to the westA wire 1.91 m long carries a current of 13.2 A and makes an angle of 39.0 with a uniform magnetic field of magnitude B = 1.90 T. Calculate the magnetic force on the wire. Number UnitsA and makes an angle of 39.0 with a uniform ma Units This answer has no units . (degrees) m kg pre. S m/s m/s^2 N W N/m kg.m/s or N.s N/m^2 or Pa kg/m^3 m/s^3 timesAn electron moves in the negative x direction, through a uniform magnetic field that is in the negative y direction. The magnetic force on the electron is: V X B O in the negative x direction O in the positive y direction O in the negative y direction O in the positive z direction O in the negative z directionIn the formula F - qu x B: O F must be perpendicular to * but not necessarily to B O F must be perpendicular to B but not necessarily to v O v must be perpendicular to B but not necessarily to F O all three vectors must be mutually perpendicular O F must be perpendicular to both v and BA straight conductor carrying a current i = 4.5 A splits into identical semicircular arcs as shown in the figure. What is the magnetic field at the center C of the resulting circular loop, which has a radius of 2.1 cm? Number Unitssplits into identical semicircular arc ich has a radius of 2.1 cm? ts V T Tom T/s I/T Wb Wb/mIn the figure, two circular arcs have radii a = 14.1 cm and b = 11.4 cm, subtend angle 0 = 75.09, carry current i = 0.440 A, and share the same center of curvature P. What are the (a) magnitude and (b) direction (into or out of the page) of the net magnetic field at P? (a) Number i Units v (b)C*m H C 14.1 cm ar subtend angle 0 = 75 a) magnitud Wb ion (into or out of th F T*m J/T T C/m^2 C/m N*m^2/C Wb/m Units Vsame center of curvature P. What are the (a (a) Number (b) V in out

Step by Step Solution

There are 3 Steps involved in it

Step: 1

blur-text-image

Get Instant Access to Expert-Tailored Solutions

See step-by-step solutions with expert insights and AI powered tools for academic success

Step: 2

blur-text-image

Step: 3

blur-text-image

Ace Your Homework with AI

Get the answers you need in no time with our AI-driven, step-by-step assistance

Get Started

Recommended Textbook for

Essential College Physics Volume 1

Authors: Andrew Rex, Richard Wolfson

1st Edition

978-0321611161, 0321611160

More Books

Students also viewed these Physics questions