Question
1 A normal distribution has a mean u = 15.2 and a standard deviation of = 0.9 . Find the probability that a score is
1
| A normal distribution has a mean u = 15.2 and a standard deviation of = 0.9. Find the probability that a score is greater than 16.1 |
A | 0.8413 |
B | 0.1587 |
C | 0.1357 |
D | 0.1550 |
2
| A normal distribution has a mean u = 67.3 and a standard deviation of = 9.3 Find P81, which separates the bottom 81% from the top 19% . |
A | 0.29 |
B | 0.88 |
C | 70.0 |
D | 75.5 |
3
| Assume the women have heights that are normally distributed with a mean of 63.6 inches and a standard deviation of 2.5 inches. Find the value of the quartile Q3 |
A | 66.1 |
B | 67.8 |
C | 65.3 |
D | 64.3 |
4 | The weights of certain machine components are normally distributed with a mean of 8.08 g and a standard deviation of 0.1 g. Find the TWO weights, one to separate the top 3% and the other to separate the bottom 3% . | |
A | 8.03 and 8.13 | |
B | 7.89 and 8.27 | |
C | 7.86 and 8.35 | |
D | 8.06 and 8.10 | |
5 | The statistic, s, is a good estimate for: | |
A | u | |
B | ||
C | ||
D |
| |
6 | How is the dispersion of a Normal distribution compare to the dispersion of a T - distribution, | |
A | Normal Distribution is more dispersed than the T distribution | |
B | Normal Distribution is less dispersed than the T distribution | |
C | Normal Distribution is dispersed in the same way as the T distribution |
7 | As the significance level decreases the chances of reject Ho increases |
A | True |
B | False |
C | Stays the same |
D | No relationship between the two statistics |
8
| The expected result of a hypothesis test are calculated under the assumption that the Null Hypothesis is which of the following: |
A | False |
B | True |
C | Depends on alpha level given |
9
| When a directional hypothesis is being tested and the rejection region is on the right side of the mean, then the alternate hypothesis must be of the form: |
A | Less than |
B | Greater than |
C | Not equal |
D | Equal |
10- 18 | Goodmoon Radial Tires CO. claims it's tires last 30,000 miles. You believe that is an over-estimate. You draw a sample of 61 tires and find the mean to be 29,995 miles with a standard deviation of 16. (Use a significance level of .05) |
10 | What would be the Null Hypothesis? |
A | = 29,995 |
B | < 30,000 |
C | = 64 |
D | > 29,995 |
E | = 30,000 |
11 | What is the Alternate Hypothesis? |
A | = 29,995 |
B | x < 30,000 |
C | > 30,000 |
D | < 30,000 |
E | U = 30,000 |
12 | What is the variance of the sample? |
A | 30,000 |
B | 29,995 |
C | 4096 16 |
D | 256 |
E | 16 |
13 | What is the sample mean outcome? |
A | 30000 |
B | 29,995 |
C | 64 |
D | 16 |
E | 2 |
14
| What is the Distribution of Sample Means (DSM) Standard deviation? |
A | 2 .05 |
B | 16 |
C | 61 |
D | 3750 |
E | 7250 |
15 | What is the degrees of freedom? |
A | 15 |
B | 16 |
C | 60 |
D | 61 |
E | 62 |
16 | What is the value of the critical cut off score? |
A | + 1.75 |
B | -1.67 |
C | +2.00 |
D | -2.43 |
E | -2.66 |
+
17 | What is the values of the computed test statistic? |
A | 0.0325 |
B | 1.25 |
C |
|
D |
|
E |
|
18 | What is the final decision? |
A | Do Not Reject Ho |
B | Do Not Reject Ha |
C | Reject Ho |
D | Reject Ha |
E | Neither reject or Do not reject, since it is a tie. |
19 | If a False Ho is found not to be rejected then what type of error might have been made? |
A | Type 1 error |
B | Type II error |
C | Type III error |
D | False error |
E | True error |
20 -29 | In 1996, the average monthly credit card balance for a population of VISA cardholders was $791, with a standard deviation of $279. It was believed that the average balance was expected to be higher in 1997. To prove that belief, a sample of 423 accounts in this population had an average balance of $831. Does this support the hypothesis that the average balance increased? (Use = 5%) |
20 | What is the Null Ho, Hypothesis? |
A | = 791 |
B | > 831 |
C | = 1996 |
D | > 791 |
E | = 831 |
21 | What is the Alternate Hypothesis? |
A | = 831 |
B | x < 791 |
C | > 831 |
D | > 791 |
E | U = 791 |
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