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1. A store owner was interested in researching the mean amount spent ($) per customer. A random sample of 76 customer transactions was collected. The

1. A store owner was interested in researching the mean amount spent ($) per customer. A random sample of 76 customer transactions was collected. The mean was $40 with a standard deviation of $5.

a)The store owner was interested in creating a 99% confidence interval to estimate the population mean spend per customer per transaction.

The store owner provided the following workings for the confidence interval:

40 +/- square root (1.96*5/76) = 38 +/- 0.359 = (39.64, 40.36) in $million

StateTHREE MISTAKES with this solution ANDEXPLAINhow you would CORRECT THESE MISTAKES,but do NOT create another confidence interval.[5 marks]

b)The store owner who created the confidence interval, offered the following interpretation:

"We are 90% confident that theprobability the customers have asample meantransaction per shop is between39.64 and 40.36 in $million.

StateTHREE MISTAKES with this solution ANDEXPLAINhow you would CORRECT THESE MISTAKES,but do NOT create another confidence interval.[3 marks]

c)The store owner collected the sample of data, by asking shoppers leaving the store, on a Wednesday afternoon, how much they had spent.Briefly explainto the store owner, an error with their sampling method. [2 marks]

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