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A wrecking ball (weight, W, = 4000 N) is supported by a boom, which may be assumed to be uniform and has a weight of Wa = 1600 N. As the drawing shows, a support cable runs from the top of the boom to the tractor. The angle between the support cable and the horizontal is 32, and the angle between the boom and the horizontal is 48. What is the tension in the support cable, T? Equation: T l sine = w, l sin d + w } sind where o is the angle that the weight of the hanging wrecking ball and the weight of the boom make with the vertical and 0 is the angle that the support cable makes with the boom at the top. I is the length of the boom and it cancels out. Support. cable Boom P 48OT = 14,226 N OT = 11,652 N O T =12,866 N O T = 13,876 N O T = 10,189 NExplanation: Free Body Diagram of the system of the crane. Step: 3 on putting their respective value; Tlsin 9 = ersin (p | Wb () sin g 1 Tsin 160 = [4,000N + 1,600 (5) ] sin 420 1 ' 420 T = [4,000N+ 1300(5)] 81\" SiIl 16o = 11,652.36N Explanation: tension in the cable along the cable as shown in diagram. Answer: the tension in the cable is T = 11,652.4N(approx)