1

An equation of a parabola is given. 7x = y2 (a) Find the focus, directrix, and focal diameter of the parabola. focus ( x, y ) = directrix focal diameter (b) Sketch a graph of the parabola and its directrix. Graph Layers After you add an object to the graph you can use Graph Layers to view and edit its properties. No Solution HelpFind an equation for the parabola that has its vertex at the origin and satisfies the given condition. Focus F(- 35, 0)Find an equation for the parabola that has its vertex at the origin and satisfies the given condition. Directrix X = 16\fA graphing calculator is recommended. Use a graphing device to graph the parabola. x2 = 36y Graph Layers After you add an object to the graph you can use Graph Layers to view and edit its properties. No Solution HelpFind an equation for the parabola that has its vertex at the origin and satisfies the given condition. FOCUS FO, -Find an equation for the parabola that has its vertex at the origin and satisfies the given condition. Directrix X = -2Find an equation of the parabola whose graph is shown. FocusAn equation of a parabola is given. x2 = 4y (a) Find the focus, directrix, and focal diameter of the parabola. focus ( x, y ) = ( directrix focal diameter (b) Sketch a graph of the parabola and its directrix. Graph Layers After you add an object to the graph you can use Graph Layers to view and edit its properties. No Solution Help\fAn equation of a parabola is given. 9x + 712 = 0 (a) Find the focus, directrix, and focal diameter of the parabola. focus (x, y) = ( directrix focal diameterFind an equation for the parabola that has its vertex at the origin and satisfies the given condition. Focus F(0, 5)