1. b) p = factors of 9 PPPPPPR 7 factors of 1 Finding a definite O: f ( 1 ) = - 9 (+ ( - 2 ) : 0 f ( - 1 ) = 1 ". one of the 3 zeros will be f ( 2 ) = - 8 (*+ 2 ) Now do sguthelive division: Leading coefficients to is there because The root cakes - 2/ 1 0 - 6 - 4 there is technically a .. D is techiniaily a leading coefficaut as - these numbers LD - 2 - 2 0 6- since it = will now be O. I know that it's been dove correcting Coefficients for Product : -2 Sum ! - L = = 13 ( +2 ) ( x - 53 ) ( x + 53 ) ( 2 2 - LX- 2 )Factor fully within real numbers, no complex numbers. b) 23- 62-4 Also, this is the textbook answer (by the way that G is actually a negative, so G1 and G2 is actually -1 and -2): b) Letf(z)= 23-6z-4. f (1) =-9 f (GI) =1 f (2 ) =-8 f (G2) =0 (=+2) is a factor. This is my solution, what have I done wrong? Did the textbook just not do all the steps? Shouldn't I be correct? Also, the method for solving I used is the Rational Zero Theorem, is this the correct method to factor fully