1. Calculate the rate of heat capacity and write a graph of the relationship from the result of the calculation shell and tube: one shell pass when given 1.1 NTU = 1 When the efficiency value of the heat exchanger is 30 % 1.2 NTU = 2 When the efficiency value of the heat exchanger is 40 % 1.3 NTU = 3 When the efficiency value of the heat exchanger is 50 % 1.4 NTU = 4 When the efficiency value of the heat exchanger is 60 % 1.5 NTU = 5 When the efficiency value of the heat exchanger is 70 % A1515 7.3 NTU relations for heat exchangers (Kays and London): NTU = UA/Cmin and c = Cmin/Cmax = ( mCp)min/(m. Cp)max Heat exchanger type NTU relation 1. Double pipe: Parallel-flow NTU = In[1-E(1+c)] 1+c Counter-flow NTU = In () (36 1 2. Shell-and-tube:One-shell pass 2,4... tube passes NTU (27 - 1-C-V1+c2 In 12/8-1-c+v1+c") V1 + c 3. Cross-flow (single-pass) In(1-EC)] Cmax mixed, Cmin unmixed NTU = In[1+ - In [1 + ] Cmin mixed, Cmax unmixed NTU = Inc In(1-5)+1] 4. All heat exchangers with c = 0 NTU = -In(1 - E)