1) Choose t or z 2: A confidence interval is to be found using a sample of size 58 and a known population deviation of 1.390. If the critical value should be a z-score, type the number 0 below If the critical value should be a t-score, type the number 1 below *The computer is looking for either the input 0 or the input 1. It will not recognize anything else you type in

2) Choose t or z 5: A confidence interval is to be found using a sample of size 338 and the sample deviation of 1.576. If the critical value should be a z-score, type the number 0 below If the critical value should be a t-score, type the number 1 below *The computer is looking for either the input 0 or the input 1. It will not recognize anything else you type in

4) margin error 1 t: A sample of weights of 23 boxes of cereal yield a sample average of 16.2 ounces. What would be the margin of error for a 90% CI of the average weight of all such boxes if the sample deviation is 0.65 ounces? The population of all such weights is normally distributed. Round to the nearest hundredth

5) simple interval 4 t: If a sample average is found to be 98.54, and the margin of error is calculated to be 0.24, then the lower end of the confidence interval for mu would be ______

6) simple interval 3 t: If a sample average is found to be 18.3, and the margin of error is calculated to be 0.01, then the lower end of the confidence interval for mu would be ______

7) TI83 interval 6 t: Use your TI83 to find the upper end of the interval requested: A 99.5% confidence interval for the average healthy human body temperature if a sample of 4 such temperatures have an average of 98.63 degrees F with a sample deviation of 0.254 degrees F The population of all such temperatures is normally distributed round to the nearest hundreth of a degree

8) TI83 interval 5 t: Use your TI83 to find the lower end of the interval requested: A 80.0% confidence interval for the average height of the adult American male if a sample of 101 such males have an average height of 58.4 inches with a sample deviation of 4.5 inches. The population of all such heights is normally distributed round to the nearest hundreth of an inch

9) TI83 interval 8 t: Use your TI83 to find the lower end of the interval requested: A 99.9% confidence interval for the average healthy human body temperature if a sample of 28 such temperatures have an average of 98.71 degrees F with a sample deviation of 0.228 degrees F The population of all such temperatures is normally distributed round to the nearest hundreth of a degree

10) TI83 interval 2 t: Use your TI83 to find the upper end of the interval requested: A 99.8% confidence interval for the average height of the adult American male if a sample of 25 such males have an average height of 59.5 inches with a sample deviation of 4.0 inches. The population of all such heights is normally distributed round to the nearest hundreth of an inch