1. Compute manually the checksums of frame A, frame B, and frame C

2. Does this agree with the checksum stored in the IP header? Explain!

Note: If I understand correctly, the checksum is stored in the second row, column 9 and 10. For example, in Frame A the checksum is ed fb

Frame A 04 a1 51 a 3 22 af 80 00 0b 94 1e 0c 08 00 45 00 0000 00 3c 53 37 00 00 80 01 ed fb c0 a8 01 0a 86 47 abcdef 0020 67 68 69 6a 6b 6c 6d 6e 6f 70 71 72 73 74 75 76 ghijklmn opqrstuv 0030 wabcdefg hi 0040 77 61 62 63 64 65 66 67 68 69 Frame B 80 00 0b 94 1e 0c 04 a1 51 a3 22 af 08 00 45 00 0000 00 3c be b8 40 00 40 06 f8 a7 c0 a8 01 01 ce a8 0010 01 0a 0f 0a 0b 35 72 79 52 8a 00 00 00 00 a0 02 ...5ry R. 0020 16 do ce 19 00 00 02 04 05 b4 04 02 08 0a 13 6a 0030 0040 ec 32 00 00 00 00 01 03 03 02 Frame C ff ff ff ff ff ff 04 a1 51 a 22 af 08 00 45 00 0000 00 c9 a7 a6 40 00 40 11 do d4 c0 a8 01 01 ff ff .2.2 0010 ff f f 04 13 1c ff 00 b5 77 57 4b 41 4e 4e 4f 55 0020 WWKANNOU 25 4e 000 000 00 00 00 04 a1 51 a 3 22 af 57 4e 44 %N. Q. WND 0030 0040 52 33 38 30 30 00 00 00 00 000 00 00 00 57 4e 44 R3800 WND 0050 52 33 38 30 30 00 00 00 00 00 00 00 00 00 00 00 R3800 0060 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 0070 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 0080 00 31 2e 30 32 2e 30 32 00 00 00 00 00 00 00 00 1.02.02 0090 00 00 00 00 000 000 00 01 00 00 00 01 00 00 00 02 00a0 00 00 00 02 00 00 00 00 00 00 00 00 00 00 00 00 00b0 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00c0 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00d0 00 00 00 00 00 00 00