1. Determine whether the given procedure results in a binomial distribution. If not, state the reason why. Choosing 5 people (without replacement) from a group of 46 people, of which 15 are women, keeping track of the number of men chosen.

Group of answer choices

Procedure results in a binomial distribution.

Not binomial: the trials are not independent.

Not binomial: there are more than two outcomes for each trial.

Not binomial: there are too many trials.

2. Find the mean,for the binomial distribution which has the stated values of n and p. Round answer to the nearest tenth. n = 2772; p = 0.63

Group of answer choices

= 1746.4

= 1741.1

= 1750.1

= 1737.9

3. Find the mean,, for the binomial distribution which has the stated values of n and p. Round answer to the nearest tenth. n = 1651; p = 0.57

Group of answer choices

= 941.1

= 948.4

= 950.8

= 933.6

4. Find the standard deviation,, for the binomial distribution which has the stated values of n and p. Round your answer to the nearest hundredth. n = 47; p = 0.4

Group of answer choices

= 6.63

= 3.36

= 0.95

= 7.48

5. Find the standard deviation,, for the binomial distribution which has the stated values of n and p. Round your answer to the nearest hundredth. n = 767; p = 0.7

Group of answer choices

= 10.28

= 12.69

= 16.81

= 15.96

6. Find the indicated probability. Round to three decimal places. Find the probability of at least 2 girls in 8 births. Assume that male and female births are equally likely and that the births are independent events.

Group of answer choices

0.109

0.965

0.035

0.855

7. Assume that a procedure yields a binomial distribution with a trial repeated n times. Use the binomial probability formula to find the probability of x successes given the probability p of success on a single trial. Round to three decimal places. n = 30, x = 12, p = 0.20

Group of answer choices

0.006

0.108

0.003

0.014

8. Assume that a procedure yields a binomial distribution with a trial repeated n times. Use the binomial probability formula to find the probability of x successes given the probability p of success on a single trial. Round to three decimal places. n = 14, x = 6 , p = 0.5

Group of answer choices

0.016

0.275

0.183

0.238

9. Solve the problem. The probability that a person has immunity to a particular disease is 0.8. Find the mean number who have immunity in samples of size 17.

Group of answer choices

0.8

8.5

3.4

13.6

10. Use the given values of n and p to find the minimum usual value- 2and the maximum usual value+ 2. Round your answer to the nearest hundredth unless otherwise noted. n = 194, p = 0.16

Group of answer choices

Minimum: -21.11; maximum: 83.19

Minimum: 41.25; maximum: 20.83

Minimum: 20.83; maximum: 41.25

Minimum: 25.93; maximum: 36.15