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1. Evaluate the following integrals x4 ( - 2 sec x + 3 - 3 sin x)dx = 1 - x2 So (11+1=12 -
1. Evaluate the following integrals x4 ( - 2 sec x + 3 - 3 sin x)dx = 1 - x2 So (11+1=12 - 2 + )dz = 3 - x4 1 -)dx = 2. Compute the following sums. 5 k 12 + 1 k=2 200 (k - 2k) = k=1
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Precalculus
Authors: Michael Sullivan
8th Edition
0321830814, 9780321830814
