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1. FieldsCircuits MI part 1 of 2 i bulb, EL be the electric field in the lower-left bulb, and E2R to be the electric

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1. FieldsCircuits MI part 1 of 2 i bulb, EL be the electric field in the lower-left bulb, and E2R to be the electric field in the lower-right bulb. Choose the answer that identifies the cor- rect statements from the following list. E2L (la) E (Ib) E > E2L (IIa) E2L > E2R = E2R (IIb) EL O1. Ia, IIa, IIIa O2. Ib, IIb, IIIb O 3. Ia, IIb, IIIa O 4. Ib, IIb, IIIa E (a) H 12 Ji'pattery 5. Ib, IIa, IIIa (IIIa) E2L + E2R (IIIb) E2L E2R > E1 == O 6. Ib, IIa, IIIb O 7. Ia, IIb, IIIb E (b) From a microscopic point of view, the im- portant quantities in a circuit analysis are the fields and the electron currents. This problem concerns the circuits shown in figures (a) and (b). The bulbs in both circuits are identical and have a filament length L, while the bat- teries are also identical with emf, . Assume the potential difference along the connecting wires in both circuits is negligible. For the case of Fig(a), the field in the fila- ment is E. The circuit satisfies the loop equa- tion: =EL and the electron current is i. Now consider the circuit of Fig(b). Define E to be the electric field through the top 8. Ia, IIa, IIIb 1. Ia, IIb, IIIb part 2 of 2 Denote the current through the top branch be and the current through the bottom. O2. Ia, IIa, IIIa branch to be i. O3. Ib, IIa, IIIb Choose the answer that identifies the cor- rect statements from the following list. O 4. Ia, IIa, IIIb (Ia) i = i (Ib) i < i 5. Ib, IIb, IIIb (IIa) i (IIb) i = = i 2 (IIIa) i battery (IIIb) i battery = 3 2 = 2i 6. Ib, IIa, IIIa O7. Ib, IIb, IIIa 8. Ia, IIb, IIIa 2. EMFinCircuitMI19x070 part 1 of 5 The following questions correspond to the figure shown, consisting of two flashlight bat- teries and two Nichrome wires of different lengths and different thicknesses as shown (corresponding roughly to your own thick and thin Nichrome wires). Your response... PALETTE + + The thin wire is 51 cm long, and its diame- ter is 0.19 mm. The thick wire is 23 cm long, and its diameter is 0.37 mm. The emf of each flashlight battery is 1.8 V. Determine the steady-state electric field in- side each Nichrome wire. Remember that in the steady state you must satisfy both the current node rule and energy conservation. These two principles give you two equations for the two unknown fields. Find the electric field in the thin wire first. Answer in units of V/m. part 2 of 5 Find the electric field in the thick wire. Answer in units of V/m. Your response... PALETTE part 3 of 5 How long does it take an electron to drift through both Nichrome wires if electron mo- bility in Nichrome is 6 10-5 (m/s)(N/C). Answer in units of s. Your response... PALETTE part 4 of 5 On the other hand, about how long did it take to establish the steady state when the circuit was first assembled? 1. 2466.67 s 2. 2.46667 s 3. 2.46667 10-9 s 4. 0.00246667 s 5. 2.46667 10-6 s part 5 of 5 There are about 6 1028 mobile electrons per cubic meter in Nichrome. How many electrons cross the junction between the two wires every second? Answer in units of electrons/s. Your response... PALETTE

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