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1. Find an equation of the tangent to the curve at the point corresponding to the given value of the parameter. x = sin(5t) +
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Find an equation of the tangent to the curve at the point corresponding to the given value of the parameter. x = sin(5t) + cos(t), y = cos(5t) - sin(t); t = n V=Find an equation of the tangent to the curve at the given point. x = tz - 3t, y = tz + 3t + 1; (0, 19) y = Graph the curve and the tangent. 30 30/ 30/ 25- 30 25- 25 201 25 204 20 15 20 15- 10 16 10- 5 10- 5 5/ 3 5 10 15 X 20 25 10 15 X 20 25 10 15 X 20 25 10 15 X 20 25 AThe Cartesian coordinates of a point are given. (a) (-8, 8) (i) Find polar coordinates (r, 0) of the point, where r > 0 and 0 5 0 0 and 0 $ 0Step by Step Solution
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