1.

Find the (a) mean1 to] median. {c} mode1 and {d} midrange for the given sample data. An experiment was conducted to determine whether a deciency of carbon dioxide in the soil affects the phenotype of peas. Listed below are the phenotype codes where 1 = smoothyellow. 2 = smoothgreen. 3 = wrinttledyellcnw1 and 4 = wrinkledgreen. Do the results make sense? 3 4 4 2 4 2 2 3 3 2 4 1 2 2 D {a} The mean phenotype code is El. {Round to the nearest tenth as needed.) to] The median phenotype code is E. [Type an integer or a decimal.) {c} Select the correct choice tieon.r and fill in any answer boxes within your choice. D A- The mode phenotype code is (Use a comma to separate answers as needed.) CI E. There is no mode. (d) The midrange of the phenotype codes is E. [Type an integer or a decimal.) Do the measures of center make sense? O A. All the measures of center make sense since the data is numerical. O B. Only the mean, median, and mode make sense since the data is numerical. O C. Only the mean, median, and midrange make sense since the data is nominal. O D. Only the mode makes sense since the data is nominal.Chi-square distribution table Area to the Right of the Critical Value Degrees of Freedom 0.995 0.99 0.975 0.95 0.90 0.10 0.001 0.004 0.016 2.706 0.010 0.020 0.051 0.103 0.211 4.605 0.072 0.115 0.216 0.352 0.584 6.251 0.207 0.297 0.484 0.711 1.064 7.779 0.412 0.554 0.831 1.145 1.610 9.236 0.676 0.872 1.237 1.635 2.204 10.645 0.989 1.239 1.690 2.167 2.833 12.017 1.344 1.646 2.180 2.733 3.490 13.362 1.735 2.088 2.700 3.325 4.168 14.684 10 2.156 2.558 3.247 3.940 4.865 15.987Conduct the hypothesis test and provide the test statistic and the critical value, and state the conclusion. A person drilled a hole in a die and filled it with a lead weight, then proceeded to roll it 200 times. Here are the observed frequencies for the outcomes of 1, 2, 3, 4, 5, and 6, respectively: 28, 30, 42, 38, 29, 33. Use a 0.10 significance level to test the claim that the outcomes are not equally likely. Does it appear that the loaded die behaves differently than a fair die? Click here to view the chi-square distribution table The test statistic is (Round to three decimal places as needed.) The critical value is (Round to three decimal places as needed.) State the conclusion. Ho- There sufficient evidence to support the claim that the outcomes are not equally likely. The outcomes to be equally likely, so the loaded die to behave differently from a fair die.Find the area of the shaded region. The graph to the right depicts IQ scores of adults, and those scores are normally distributed with a mean of 100 and a standard deviation of 15. 106 128 The area of the shaded region is (Round to four decimal places as needed.)