1. Find the size of the delay of the code snippet below if the crystal frequency is 4MHz.

R2 equ 0x07

R3 equ 0x08

Delay

MOVLW 200

MOVWF R2

AGAIN

MOVLW 250

MOVWF R3

HERE

NOP

NOP DECF R3, F

BNZ HERE

DECF R2, F

BNZ AGAIN RETURN

2. Find the number of times the following loop is performed:

REGA equ 0x20

REGB equ 0x30

...

MOVLW 200

MOVWF REGA

BACK MOVLW 100

MOVWF REGB

HERE DECF REGB,F

BNZ HERE

DECF REGA, F

BNZ BACK

3. Find the oscillator frequency if the instruction cycle =1.25us.

4. Find the instruction cycle if the crystal frequency is 20MHz.

5. Write a macro that divides a number by any number in power of two and stores the result in the memory location.

6. Store the following array of numbers in the program memory starting at 0x200 and then add them together and store the result in the data memory 0x20 and 0x21. Array db 0x02, 0x14, 0x30, 0x34, 0xA1, 0x00, 0xBD, 0x57,0x99,0xFF

7. Write a program that generates a one-second delay.