Question
1. For an individual with Type O blood, choose all possible blood types of their children. Type Type A Type B Type AB 2. Match
1. For an individual with Type O blood, choose all possible blood types of their children.
- Type
- Type A
- Type B
- Type AB
2. Match the statement/condition on the left with the type of dominance relationship on the right. Answers can be used once, more than once or not at all.
Phenotype is a blending of the two alleles ................. Incomplete dominance
One allele will mask the other allele............................ Standard dominance -
Neither allele is fully dominant over the other.......... Both Incomplete and Co-
F1 phenotype shows both alleles................................ Co-dominance
F2 generation has three distinct phenotypes............ Incomplete dominance
3. Plant height in pea plants is controlled by a single gene. Tistallwhilet is short. Match the genotype on the left with possible progeny on the right. Note you are only given ONE genotype and not a cross. Choose all possible progeny for the genotype on the left.
A heterozygous individual can give rise to progeny either dominant or recessive depending on genotype of the other parent.
A heterozygous individual can give rise to progeny either dominant or recessive depending on genotype of the other parent.
A homozygous recessive individual can produce either dominant or recessive depending on genotype of the other parent.
he two er allele [Choose ] Sex linked Incomplete dominance Standard dominance Sex influenced Both Incomplete and Co-dominance Co-dominance Tt Ttx Tt will produce Tt x TT will produce Tt x tt will produce 25% TT - Tall 0% TT = Tall 50% Tt - Tall 50% TT= Tall tt Tall only 50% Tt = Tall 50% Tt - Tall 25% tt = short 0% tt = short 50% tt = short A heterozygous individual can give rise to progeny either dominant or recessive depending on genotype of the other parent. Short only Ttx Tt will produce 25% TT= Tall 50% Tt-Tall 25% tt = short Tt x TT will produce Tt x tt will produce 50% TT = Tall 0% TT - Tall 50% Tt = Tall 0% tt = short 50% Tt - Tall 50% tt = short Tt x Tt will produce Tt x TT will produce Tt x tt will produce 25% TT-Tall 50% TT - Tall 0% TT-Tall 50% Tt - Tall 50% Tt - Tall 50% Tt - Tall 25% tt-short 0% tt-short 50% tt-short tt x Tt will produce tt x TT will produce tt x tt will produce 0% TT-Tall 100% TT-Tall 0% TT - Tall 50% Tt - Tall 0% Tt - Tall 50% tt-short 0% tt-short 0% Tt - Tall 100% tt-short
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