1.

\fProve that the area of a parallelogram is the product of two adjacent sides and the sine of the included angle. Let A be the area of the parallelogram. According to the given figure, what conclusion should be proved? $1$2 O A. A= sins S1 + 52 OB. A= sin S O C. A= ($1 + $2) sin S OD. A=$1 $2 Sin S In order to prove the identity found in the previous step, start with the formula of the area of the parallelogram. Let h be the height of the parallelogram, as shown to the right. Find the area A. $1 A = V In the right triangle SAB, express h in terms of s, and S. h = What is the next step to complete the proof? O A. Subtract the expression of h found in the previous step from the formula of the area of the parallelogram. O B. Multiply the expression of h found in the previous step by the formula of the area of the parallelogram. O C. Substitute the expression found in the previous step for h into the formula of the area of the parallelogram. O D. Add the expression of h found in the previous step to the formula of the area of the parallelogram.Sketch the pair of vectors and determine whether they are equivalent. Use the ordered pairs A( - 1,2), B(4,4), G{ -4,5), and H(1 ,1) forthe initial and terminal points. I- r- GA, BH 4 > Are the vectors equivalent? Select the correct choice below and ll in the answer box(es) to complete your choice. C3 A- Yes. Both vectors have a magnitude of (Simplify your answer. Type an exact answer, using radicals as needed.) C3 B- No. Both vectors have a magnitude of (Simplify your answer. Type an exact answer, using radicals as needed.) A c _.. . U ' No. Vector GA has a magnitude of (Simplify your answers. Type exact answers, using radicals as needed.) and travel in the same direction. but travel in different directions. _* while vector BH has a magnitude of