@1 Geometry w/Da X @ Geometry w/Da X @, Geometry w/Da X (5) 1203 Measure X @ Schoology X @ Schoology X t Course Hero Microsoft Word 0' e.schoology.com 1/6) 0 119%0 Part I: Below are the results of 49 throws at the dartboard at the right. The colored areas are numbered from 9 points in the center to 1 in the outside ring. Use the results shown in the histogram to answer problems 1 and 2. Hm:LLLLz11113 111111114 11111111115 111111116 Izzzz11119 We can plot the distribution of the 49 values. The scores from 1 to 9 are shown on the horizontal axis. The vertical axis tells how many hits there were at each specific value. This data is totally symmetric, so it is a normal distribution. 1, Find the mean of the data by using the following formula. Double check your work. Vou will need this value to work problem 2. [l 2 xi ' 11 Remember, you are still finding mean by adding the values in the data set and dividing by the number of entries. The numerator of . 2'\" means to add the values in the data set. The denominator, n, represents the number of items in the data set. Geometry w/Data X S Geometry w/Data X Geometry w/Data X S 12.03 Measure of X S Schoology X S Schoology X Course Hero X Microsoft Word - X C bcbe.schoology.com/attachment/2336994993/docviewer . . . Apps 2 /6 > 119% |+| I ab 2. Fill in the following table and then calculate the standard deviation of the data. Remember, A is the mean (from problem 1), x; is the number in the 2nd column. N is the number in the 1st column. Times (xi - 1 ) ( xi - 1 ) 2 N(xi - M) 2 repeated, N 2 1 3 2 9 -A 11 2 9 E(xi-H)2 O = n 0 = E means sum (add). S