1) If the level of significance in a test is 0.05, and the p-value is 0.0002, you...
Question:
1)
If the level of significance in a test is 0.05, and the p-value is 0.0002, you would
a. | Reject the null and accpt the alternative | |
b. | Fail to reject the null |
2)
If the p-value of a test is 0.12, at the default alpha you would
a. | Reject the null and accept the alternative | |
b. | Fail to reject the null |
3)
If the level of significance in a test is 0.05, and the p-value is 0.0002, you would
a. | have insufficient evidence for the alternative | |
b. | have sufficient evidence for the alternative |
4)
If the p-value of a test is 0.00000013, then at the default alpha you would
a. | Reject the null and accept the alternative | |
b. | Fail to reject the null |
5)
If the level of significance in a test is 0.01, and the p-value is 0.025, you would
a. | have insufficient evidence for the alternative | |
b. | have sufficient evidence for the alternative |
6)
If the p-value of a test is is 0.12 at the default alpha, you would
a. | have insufficient evidence for the alternative | |
b. | have sufficient evidence for the alternative |
7)The amount of time a student takes to finish an online algebra quiz is normally distributed. A hypothesis test is conducted to determine if the time students are taking is, on the average, is not 36 minutes. Use your TI83 to determine the p-value of the test (to the nearest thousandth) if a sample of size 22 yields a mean of 46 minutes and a standard deviation of 30 minutes
8)The amount of time a customer waits in a fast-food frive-thru is normally distributed. A test is conducted to determine if the customers are waiting, on the average, more than 60 seconds. Use your TI83 to determine the p-value of the test (to the nearest thousandth) if a sample of size 25 yields a mean of 78 seconds and a standard deviation of 25 seconds
9)The amount of time a student takes to finish an online algebra quiz is normally distributed. A hypothesis test is conducted to determine if the time the students are taking is, on the average, more than 60 minutes. Use your TI83 to determine the p-value of the test (to the nearest thousandth) if a sample of size 25 yields a mean of 72 minutes and a standard deviation of 20 minutes
10)
The z-score for the sample mean used in a hypothesis test is called a
a. | level of confidence | |
b. | critical value | |
c. | test statistic | |
d. | level of significance |
11)
The alternative hypothesis in a test states the
a. | level of confidence | |
b. | claimed value of mu | |
c. | suspected change in mu | |
d. | level of significance |
12)
A statistical test will generate proof rather than mere evidence
a. | TRUE | |
b. | FALSE |
13)
A statistical test will determine the true value of the population mean mu
a. | TRUE | |
b. | FALSE |
14)
The alternative hypothesis may be written in one of how many different forms?
a. | 1 | |
b. | 2 | |
c. | 3 | |
d. | 4 |
15)
What determines that you should use a t-distribution to get a critical value for a hypothesis test?
a. | The population deviation is being used | |
b. | The sample deviation is being used | |
c. | The sample size is small | |
d. | the sample size is large |
16)
A t-test produces a p-value of 0.15. The type of evidence found in favor of the alternate hypothesis is
a. | little | |
b. | moderate | |
c. | strong | |
d. | very strong |
17)
If a population is not normally distributed, what must be true in order to do a t-test for mu, using a sample average?
a. | x-bar is greater than or equal to 30 | |
b. | the sample is normal | |
c. | n is greater than or equal to 30 | |
d. | n is less than 30 |
18)A statistical test is conducted at the 0.002 level of significance. The p-value for the test is determined to be 0.00035. If there is sufficient evidence in support of the alternative hypothesis (the null is rejected) type the number 0 If there is not enough evidence to support the alternative (failure to reject the null), type the number 1
19)A statistical test is conducted at the 0.007 level of significance. The p-value for the test is determined to be 0.077. If there is sufficient evidence in support of the alternative hypothesis (the null is rejected) type the number 0 If there is not enough evidence to support the alternative (failure to reject the null), type the number 1
20)
A cereal company claims the average weight of a box of their cereal is 18.00 ounces. A quality control technician is worried that the boxes are over-filled and will to see if the average weight of the sample supports that hypothesis. A sample of 2500 boxes of the cereal are analyzed, and yield an average weight of 17.99 ounces with a standard deviation of .04 ounces. The alternative hypothesis for this problem is that mu
a. | equals 18 | |
b. | equals 17.99 | |
c. | not equal to 18 | |
d. | is greater than 18 |
21)
If little evidence can be found to favor the alternate hypothesis, we would
a. | reject H(0) | |
b. | Accept H(0) | |
c. | Fail to reject H(0) | |
d. | Accept H(a) |
22)
A cereal company claims the average weight of a box of their cereal is 18.00 ounces. A quality control technician must test to see if the average weight is different. A sample of 2500 boxes of the cereal are analyzed, and yield an average weight of 17.99 ounces with a standard deviation of .04 ounces. The null hypothesis for this problem is that mu
a. | equals 18 | |
b. | equals 17.99 | |
c. | not equal to 18 | |
d. | not equal to 17.99 |
23)A claim is made that the average human IQ is 102. A sample of 50 such IQs yields a sample average of 107. If the population deviation is 15, determine the p-value (nearest thousandth) to test that population average IQ is greater than 102
24) A claim is made that the average human IQ is 105. A sample of 58 such IQs yields a sample average of 108. If the population deviation is 17, determine the p-value (nearest thousandth) to test that population average IQ is not 105
25)A claim is made that the average healthy human body temperature is 98.596 degrees F. A sample of 55 such temperatures yields a sample average of 98.555 degrees F. If the population deviation is 0.272 degrees F, determine the p-value (nearest thousandth) to test that population average temperature is less than 98.596
26)
A cereal company claims that the average weight of a box of Sugar Toast Crunchies is 16.5 ounces. A qualty control technician has the job of monitoring the average weight on an hourly basis to make sure the poroduction process is not off target in either direction. Regular testing is conducted with 40 boxes every half hour at a 1% level of significance. The p-value from one such test turns out to be 0.08. Write, as per the Notes, the formal conclusion for this test.
27) A claim is made that the average healthy adult human body temperatures is 98.6 degrees F. Suspecting this value has decreased in the last 10 years, we test using a sample of 36 such temperatures (mean = 98.56) and the sample deviation (0.45). The p-value turns out to be 0.396. Write, as per examples, the formal conclusion.
please answer alll