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1. Imagine that we change LC-3 memory to contain 16MB of byte-addressable memory. In other words, 2 24 addresses, each holding 8 bits. Instructions are
1. Imagine that we change LC-3 memory to contain 16MB of byte-addressable memory. In other words, 224 addresses, each holding 8 bits. Instructions are now 32 bits long (so now each instruction takes four consecutive memory locations).
How many bits are now needed for the PC?
How many bits are now needed for the IR?
How many bits are now needed for the MAR?
How many bits are now needed for the MDR?
Is instruction fetch faster, slower, or unaffected? Explain your answer
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