Answered step by step
Verified Expert Solution
Link Copied!

Question

1 Approved Answer

1 in 2.54 cm Constants, Material Properties, Conversion Factors, and Vector Mathematics sin k = 1.38 10-23 J/K = g 9.81 m/s 2T 2

image text in transcribed

1 in 2.54 cm Constants, Material Properties, Conversion Factors, and Vector Mathematics sin k = 1.38 10-23 J/K = g 9.81 m/s 2T 2 = 360 = 1 rev NA = 6.02 1023 mol 1 R = 8.31 J/(molk) COS A = G = 6.673 10-11 Nm/kg |A| = A = 2 Ax + Ay 2 tan 0 Equations opposite Ay hypotenuse 4712 adjacent Ax hypotenuse opposite Ay adjacent Ax r 0 = 1 at + wot + 00 Ax = x f - Xo ac = rw At = tf - to Axtotal Ax1 + Ax2 + +Axn Fc = mac = m- xf - Xo v = Vavg At tf - to = At at = ar M1M2 FG G r2 KE mv a = aavg = 1 at + vot + xo x = v = at + vo r = Daug = {y} Vavg,x \Vavg,y Vavg, x Vavg,y Caug aavg,x At aavg,y Saavg,x \aavg,y At x = axt + voxt + xo y = ayt + voyt + Yo vx = axt + vox vy = ayt + voy vos UMS + VOM Fnet = F + F+ Fnet = F = m Fg = w = mg ... w = at + wo W Fd cos 0 Wnet Wnet = AKE W1 W2 + Wn KE - KEi PE, = mgh Fspring = kx PE=kx E=KE+PE Ei+Wnc Eff - = P = Ef Wout Ein I = Icom + mh Tnet == Ia M V F P = A P = Po + hpg Pgauge = hpg Toc = (ToF - 32) TK Toc+273.15 = AV = BVAT B 3a PV = NkT n = N PV = nRT Q = mcAT Qf = mL f Qv = mLv W t kA(TH-TC) d t t Pnet =A (Te env -14) p = mv At Ptot Pot (isolated system) AU=Q-W WQin Qout W = PAV Fnet = Impulse = Fnet At = Ap W Eff = Ap = Favg At QH + Fn Tc Effc = 1 P1 + P2 = p + p2 |QL | 7 = r F sin 0 K -= Tnet T1 T2 + + Tn Fout Kc = MA Fin s = re lin MA Wavg lout rin MA = rout Xavg I mr2 fk = kN fs,max=s N v = rw = |W| TL TH-TL Itot = 11+ 12+ + In

Step by Step Solution

There are 3 Steps involved in it

Step: 1

blur-text-image

Get Instant Access to Expert-Tailored Solutions

See step-by-step solutions with expert insights and AI powered tools for academic success

Step: 2

blur-text-image

Step: 3

blur-text-image

Ace Your Homework with AI

Get the answers you need in no time with our AI-driven, step-by-step assistance

Get Started

Recommended Textbook for

Engineering Mechanics Statics

Authors: Russell C. Hibbeler

11 Edition

9780132215091, 132215004, 132215098, 978-0132215008

More Books

Students also viewed these Mechanical Engineering questions

Question

What are the key elements of a system investigation report?

Answered: 1 week ago