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1. Let u be a differentiable function of x with |u | 2 1. By using Theorem 7 in Page 392, du Thomas's Calculus 14th

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1. Let u be a differentiable function of x with |u | 2 1. By using Theorem 7 in Page 392, du Thomas's Calculus 14th Edition, show that arc cscu) = -- lu| >1. dx lulvuz -1 dx Hence, find (a) arc csc(cosh 3x) ), dx d 3 (b) In Vx2 +1 arccos dx + 1 Simplify your answers

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